-1.#IND

[Erich Reisenhofer]

Hello!

Which operatiaon causes -1.#IND ? I use complex numbers. Thank you!

Erich

[Moonlit]

Hi,

I believe it is an infiinite number (you might have done a divide by zero
and interrupts turned off). I think you can find it in the manuals at intel
for the processor you are using (the floating parts).

Regards, Ron AF Greve.
"Erich Reisenhofer" <er***************@gmx.at> wrote in message
news:3f***********************@aconews.univie.ac.a t...

Hello!

Which operatiaon causes -1.#IND ? I use complex numbers. Thank you!

Erich

[Jerry Coffin]

In article <3f***********************@aconews.univie.ac.at> ,
er***************@gmx.at says...

Hello!

Which operatiaon causes -1.#IND ? I use complex numbers. Thank you!

That's how Microsoft's compilers print out a Quiet NaN (Not a Number).
It's typically the result of working with a variable that hasn't been
initialized (the IND stands for "indefinite" if I'm not mistaken).

Another post mentioned infinity. At least with MS's compilers, a
infinity will print out as -1.#INF. This is typically produced by a
division that produces a result too large to represent, such as
something like 1e+300/1e-300. With infinite range available, this would
produce 1e+600, but a double normally tops out at around 1e+308.

--
Later,
Jerry.

The universe is a figment of its own imagination.