To read the file after reading the filename from the directory

[shilpagangadhara]

Hi All,
I'm trying to open a directory and after getting the file names from the the directory i need to read the contents of the file.

OS ----Unix
Language C

I have done the following:

int main()
{
   DIR *dirPtr;
   struct dirent *filenamePtr;
   FILE *fp = NULL;
   long int FILESIZE = 0;
   char *buffer = NULL;
   char *temp = NULL;
   int i = 0;
   int length = 0;
   int Rfseek = 0;
   size_t bytesRead = 0;
   char *name1 = ".";
   char *name2 = "..";
   char *space = " ";
   int valName1 = 0;
   int valName2 = 0;
   const char *dirName = "/home/shilpabo/testresults";
 
   buffer = (char*)malloc(sizeof (char) *200);
   memset(buffer, 0x00 , sizeof (char) *200) ;
   temp = buffer;
 
   dirPtr = opendir(dirName);
   if(dirPtr == NULL)
   {
     printf("opendir failed\n");
     return 0;
   }
 
   else if(dirPtr != NULL)
   {
     printf("Directory is now opened to read the files\n");
 
 
     while((filenamePtr = readdir(dirPtr)) != NULL)
     {
       printf("The files are %s\n", filenamePtr->d_name);
 
       valName1 = strcmp(name1,  filenamePtr->d_name);
       valName2 = strcmp(name2,  filenamePtr->d_name);
 
       if((valName1 != 0) && (valName2 != 0))
       {
 
         strcpy(buffer,filenamePtr->d_name);
         buffer += strlen(filenamePtr->d_name);
         length = strlen(filenamePtr->d_name);
 
          strcpy(buffer, space);
         buffer++;
 
 
         fp = fopen(filenamePtr->d_name, "r");
         if(fp == NULL)
         {
           printf("The file %s cannot be opened\n", filenamePtr->d_name);
         }
 
         Rfseek = fseek(fp, 0, SEEK_END) ;
 
         FILESIZE = ftell( fp ) ;
 
         rewind(fp) ;
 
         bytesRead = fread(buffer, 1, FILESIZE, fp) ;
         buffer += FILESIZE;
 
        fclose(fp);
 
       }
 
      }
    }
 
     closedir(dirPtr);
     printf("buffer = %s\n", temp);
 
 
   return 0;
 
}

This program when i test on clear case in my Application gives an error:
The file XXXX cannot be opened.

I tried a lot but could not find out the mistake.

Kindly help me out..Its high priority..

Kind Reagrds,
Shilpa