filling numbers from a file to an array

[pallavi27]

hii,
i am working in c and my problem is that i have created a file which contains numbers,i want to store these numbers in an array.,please guide me how to go about it this is the part of code that i have written ,it is showing hundred numbers but all values are same and it shows 277 866 100 times.

while((ch=fgetc(fp)!=NULL)
{
for(i=0;i<10;i++)
for(j=0;j<10;j++)
{
image[i][j]=ch;
printf("%d %d",image[i][j]);
}

[horace1]

put the read in the loops?

 
{
for(i=0;i<10;i++)
for(j=0;j<10;j++)
{
ch=fgetc(fp);
image[i][j]=ch;
printf("%d %d",image[i][j]);
}

fegtc() reads characters, should you use

scanf("%d", image[i][j]);

[pallavi27]

put the read in the loops?

 
{
for(i=0;i<10;i++)
for(j=0;j<10;j++)
{
ch=fgetc(fp);
image[i][j]=ch;
printf("%d %d",image[i][j]);
}

fegtc() reads characters, should you use

scanf("%d", image[i][j]);

sorry this didn't worked if possible can you give any other solution to this

[pallavi27]

i am working in c and i have created a file which contains 100 numbers.i want to store these numbers in an array like a[10][10].how to do this.please give the code to do tjis.i have displayed the numbers on the screen but after that i want to store the numbers in an array.please help its urgent.

[pallavi27]

i am working in c and i have created a file which contains 100 numbers.i want to store these numbers in an array like a[10][10].how to do this.please give the code to do tjis.i have displayed the numbers on the screen but after that i want to store the numbers in an array.please help its urgent.
the code is as follows:
#include<stdio.h>
#include<conio.h>
main()
{
FILE *fp;
int i,,j,a[10][10];
char ch;
fp=fopen("abb.txt","r");
if(fp==NULL)
{
printf("Cannot open file");
exit();
}
while((ch=fgetc(fp))!=EOF)
{
for(i=0;i<10;i++)
for(j=0;j<10;j++)
{
ch=fgetc(fp);
image[i][j]=ch;
printf("%d %d",image[i][j]);
}
}
fclose(fp);
}
:

[r035198x]

i am working in c and i have created a file which contains 100 numbers.i want to store these numbers in an array like a[10][10].how to do this.please give the code to do tjis.i have displayed the numbers on the screen but after that i want to store the numbers in an array.please help its urgent.
the code is as follows:
#include<stdio.h>
#include<conio.h>
main()
{
FILE *fp;
int i,,j,a[10][10];
char ch;
fp=fopen("abb.txt","r");
if(fp==NULL)
{
printf("Cannot open file");
exit();
}
while((ch=fgetc(fp))!=EOF)
{
for(i=0;i<10;i++)
for(j=0;j<10;j++)
{
ch=fgetc(fp);
image[i][j]=ch;
printf("%d %d",image[i][j]);
}
}
fclose(fp);
}
:

1.) Do not double post
2.)Post code using code tags
3.)Haven't you already put the values in the array called image?

[Ganon11]

Why do you need the while loop? It is supposed to execute until the end of file, but it works by reading in a character - then, in your loop, you read in a new character, meaning the first is lost. You should just have the for...loops, no while loop.

Also, in your printf call, you use %d twice to indicate you are printing two values, but you only include a[i][j] to be printed - should you only have one %d?

[gpraghuram]

HI,
Can you provide me a sample of your input file...
i can give a try to help you with code.
Thanks
Raghuram

[pallavi27]

HI,
Can you provide me a sample of your input file...
i can give a try to help you with code.
Thanks
Raghuram

HII.
my text file contains numbers every row having 10 numbers.
as given below


3 3 4 5 6 6 .3
3 3 3 3 6 3..3
2
2 .............
2 3 4 5 6 7 3

[gpraghuram]

Hi,
The problem with your code was reading the integer with fgetc
try this one...

#include<stdio.h>
 
int main()
{
    int read_arr[10][10];
    char ch;
    int i=0,j=0;
    char read_array[200];
 
    FILE *fptr=fopen("ip_3.txt","r");
    if(fptr != NULL)
    {
        while(!feof(fptr))
        {
            for(j=0;j<=10;j++)
            {
                fscanf(fptr,"%d ",&(read_arr[i][j]));
                printf("%d ",i,j,read_arr[i][j]);
            }
            printf("\n");
            i++;
        }
        fclose(fptr);
    }
}
 

Thanks
Raghuram

[pallavi27]

Hi,
The problem with your code was reading the integer with fgetc
try this one...

#include<stdio.h>
 
int main()
{
    int read_arr[10][10];
    char ch;
    int i=0,j=0;
    char read_array[200];
 
    FILE *fptr=fopen("ip_3.txt","r");
    if(fptr != NULL)
    {
        while(!feof(fptr))
        {
            for(j=0;j<=10;j++)
            {
                fscanf(fptr,"%d ",&(read_arr[i][j]));
                printf("%d ",i,j,read_arr[i][j]);
            }
            printf("\n");
            i++;
        }
        fclose(fptr);
    }
}
 

Thanks
Raghuram

thanks for your program but
sorry this too didn't work.
your program shows the output :
0000000000
1111111111
2222222222
3333333333
4444444444
5555555555
6666666666
7777777777
8888888888
9999999999
but i want that it should display the numbers that i have saved in a notepad file.
and also i didn't get why you initialised the same array twice with different datatypes.it is giving error.array initialised more than once..

[Ganon11]

thanks for your program but
sorry this too didn't work.

This is why you shouldn't copy & paste someone else's code without checking it yourself first. There are several things wrong with this code. For one, the for...loop starts j at 0 and has an end condition of j <= 10, meaning there will be a total of 11 executions. This will make you run out of numbers and also read data past the bounds of read_arr. Also, the printf call gives room for one output, but tries to output i, j, and read_arr[i][j].

[gpraghuram]

Hi,
The problem was the printf statement
printf("%d ",i,j,read_arr[i][j]);

Change this to
printf("%d ",read_arr[i][j]);

Thanks
Raghuram