Simple iterator question

[michael]

Hi All,

I have :

#include <iostream>
#include <list>
using std::cout;
using std::list;
using std::endl;

class MyClass {
private:
int myVar;
public:
MyClass(int v):myVar(v){};
int getVar(){return myVar;};
void setVar(int var){myVar = var;};
};

void someFunc(Not sure what to put here c){}

int main(){
list<MyClass myList;
list<MyClass>::iterator it;

for(int i = 0; i < 5; i++){
MyClass element(i);
myList.push_front(element);
}

for(it = myList.begin(); it != myList.end(); it++){
if(*it.getVar() == 2){
//someFunc(it);
}
}
cout << "done" << endl;
}

(I know I have some magic numbers, please ignore these, I am just trying to
get the iterator stuff clear in my head.)

I have two questions:
1. Why can I not access the members of MyClass using *it.memb_name()? If I
make it a list of MyClass* I can use (*it)->memb_name(), so why when I have
a list of MyClass does *it.getVar() cause the compiler to complain thet
getVar() is undeclared?

2. How (can I?) pass the iterator to another function? What prototype would
I use?

Thanks for your help

Regards

Michael

[Jim Langston]

"michael" <sp**@begone.netwrote in message
news:46**********************@per-qv1-newsreader-01.iinet.net.au...

Hi All,

I have :

#include <iostream>
#include <list>
using std::cout;
using std::list;
using std::endl;

class MyClass {
private:
int myVar;
public:
MyClass(int v):myVar(v){};
int getVar(){return myVar;};
void setVar(int var){myVar = var;};
};

void someFunc(Not sure what to put here c){}

int main(){
list<MyClass myList;
list<MyClass>::iterator it;

for(int i = 0; i < 5; i++){
MyClass element(i);
myList.push_front(element);
}

for(it = myList.begin(); it != myList.end(); it++){
if(*it.getVar() == 2){
//someFunc(it);
}
}
cout << "done" << endl;
}

(I know I have some magic numbers, please ignore these, I am just trying
to
get the iterator stuff clear in my head.)

I have two questions:
1. Why can I not access the members of MyClass using *it.memb_name()? If I
make it a list of MyClass* I can use (*it)->memb_name(), so why when I
have
a list of MyClass does *it.getVar() cause the compiler to complain thet
getVar() is undeclared?

Operator precidence. Try
(*it).memb_name();

2. How (can I?) pass the iterator to another function? What prototype
would
I use

I think
void MyFunc( std::list<MyClass>::iterator it )
should work, but have never tried.

[red floyd]

michael wrote:

Hi All,
[redacted]

int main(){
list<MyClass myList;
list<MyClass>::iterator it;

for(int i = 0; i < 5; i++){
MyClass element(i);
myList.push_front(element);
}

for(it = myList.begin(); it != myList.end(); it++){

Prefer the prefix form of increment: ++it

if(*it.getVar() == 2){
//someFunc(it);
}
}
cout << "done" << endl;
}

(I know I have some magic numbers, please ignore these, I am just trying to
get the iterator stuff clear in my head.)

I have two questions:
1. Why can I not access the members of MyClass using *it.memb_name()?

Look up the releative precedences of unary operator* and operator. Use
either (*it).memb_name(), or it->memb_name().

2. How (can I?) pass the iterator to another function? What prototype would
I use?

void f(list<MyClass>::iterator);

for (it = myList.begin(); it != myList.end(); ++it)
f(it);

[Christopher Pisz]

"michael" <sp**@begone.netwrote in message
news:46**********************@per-qv1-newsreader-01.iinet.net.au...

Hi All,

I have :

#include <iostream>
#include <list>
using std::cout;
using std::list;
using std::endl;

class MyClass {
private:
int myVar;
public:
MyClass(int v):myVar(v){};
int getVar(){return myVar;};
void setVar(int var){myVar = var;};
};

void someFunc(Not sure what to put here c){}

int main(){
list<MyClass myList;
list<MyClass>::iterator it;

for(int i = 0; i < 5; i++){
MyClass element(i);
myList.push_front(element);
}

for(it = myList.begin(); it != myList.end(); it++){
if(*it.getVar() == 2){
//someFunc(it);
}
}
cout << "done" << endl;
}

(I know I have some magic numbers, please ignore these, I am just trying
to
get the iterator stuff clear in my head.)

I have two questions:
1. Why can I not access the members of MyClass using *it.memb_name()? If I
make it a list of MyClass* I can use (*it)->memb_name(), so why when I
have
a list of MyClass does *it.getVar() cause the compiler to complain thet
getVar() is undeclared?

2. How (can I?) pass the iterator to another function? What prototype
would
I use?

Thanks for your help

Regards

Michael

1)
Did you try it->memb_name?
Or (*it).member_name?
*it.member_name doesn't work because you are trying to dereference the whole
thing.
Same reason you had to use parens with the list of pointers, where it was
(*it)->member_name;

2)
why not?
void someFunc( list<MyClass>::iterator it)
{
}

[Paul Holden]

On Mar 27, 3:59 am, red floyd <[e-mail]:

michael wrote:

for(it = myList.begin(); it != myList.end(); it++){

Prefer the prefix form of increment: ++it

It might be worth elaborating on the reasons why:

http://www.parashift.com/c++-faq-lit...html#faq-13.15