Converting a .wav file to binary strings

[jamesd]

First off my programming experience is very limited and I haven't used C/C++ in the past 4/5 years so I'm fairly c**p at it.

Basically I'm trying to write a function that opens a .wav file and store the binary version of this file in a variable named 'input'. 'input' is a [num]x[16] integer array. 'num' is the no. of bits in the array divided by 16 (rounded up). The following is my code:

using namespace std;
 
FILE *fp;
 
int main(int argc, char *argv[]) 
{
    int *inp, num, i=0, j=0, k=0;
    long size;
    if((fp=fopen("out.wav","rb"))==NULL) {
    printf("cannot open file\n");
    exit(1);
    }
 
 
    fseek (fp, 0, SEEK_END);
    size= ftell(fp);
    printf("size of my file is %ld bits\n",size);
    fseek (fp, SEEK_CUR, SEEK_SET);
 
    inp = (int *) calloc(size, sizeof(int));
 
    fread(inp,size,1,fp);
    fclose(fp);   
    //printf("%f", inp);
    /*
    for(int i=0; i<size; i++)
    {    
         printf("%d", inp[i]);     
    }
    */
    printf("\n");
 
    num = size/16;
 
 
    if(size%num!=0)
    num++;
    printf("The size of this file can be represented by %d hexadecimal numbers \n", num);
    int input[num][16];
 
    k=0;
 
    for(i=0; i<num; i++)
    {
         for(j=0; j<16; j++)
         {
              (input)[i][j] = (*inp+k);//[k];
              k++;
         }
 
    }  
                 printf("\nThe following is the third input:\n");
                 for(int jj=0; jj<16; jj++)
                 {
 
                          if (jj%4!=0)
                          {
                                     //printf(" %d",input[3][jj]);
                                     printf(" %d",input[3][jj]);
                          }
                          else
                          {
                              //printf("      %d",input[3][jj]);
                              printf(" %d",input[3][jj]);
                          }
                 }
                 printf("\n\n");
 
 
 
    //run encryption code for all arrays!
 
    system("PAUSE");
    return EXIT_SUCCESS;
}
 

When I compile the above code and I printf one of the rows of the variable input the screen prints out 16 10-digit numbers(presumably that's the address). I'm expecting input to be a matrix with rows of size 16 containing 1's and 0's. If anyone can suggest where I might be going wrong it would be much appreciated.

[DeMan]

Consider
The line:

 (input)[i][j] = (*inp+k);//[k]; 
 

store at input[i][j] the Value at inp with k added.

Firstly, you would want *(inp+k) // the value k positions beyond inp.

Secondly input is an array of integers, so the value at this location is 32 bits (not 1). Furthermore, the compiler tries to be clever and (inp+k) is actually k int-lengths beyond inp, not k bits.

Using the same sort of array you already have, you could create a function that creates binary values by :

input[a][0] == (value >> 16) &1;
input[a][1] == (value >> 15) & 1;
input[a][2] == (value >> 14) & 1;

(ie right shift x bits (and use logical and to only worry about the last bit);

Or there is probably a way to output binary (You might like to see if this link helps you at all.

Good luck!