char array to string?

[pentiumPunk]

Hi, I created an array of characters and want to convert that array to a
string.
I want to do something like this :

char array1 [25]; //with letters already in it
string string1;
string1 = array1;

That wont work will it? what would be the proper syntax? thanks in ahead!

[Noah Roberts]

pentiumPunk wrote:

Hi, I created an array of characters and want to convert that array to a
string.
I want to do something like this :

char array1 [25]; //with letters already in it
string string1;

Change to "string string1(array);" assuming that your char array is null
terminated.

NR

[Ivan Vecerina]

"pentiumPunk" <Br***@triad.rr.com> wrote in message
news:Tl*********************@twister.southeast.rr. com...

Hi, I created an array of characters and want to convert that array to a
string.
I want to do something like this :

char array1 [25]; //with letters already in it
string string1;
string1 = array1;

That wont work will it? what would be the proper syntax? thanks in ahead!

If the string in array1 is null-terminated:
string1.assign( array1 );
or, better, direct initialization:
string string1( array1 );

If array1 is not null-terminated:
string1.assign( array1, array1+25 );
or: string1.assign( array1, 25 );
And there is a pair of matching constructors that
accept the same parameters:
string string1( array1, array1+25 );
or: string string1( array1, 25 );

Too much choice indeed...

hth
--
Ivan Vecerina, Dr. med. <> http://www.post1.com/~ivec
Brainbench MVP for C++ <> http://www.brainbench.com

[John Harrison]

"pentiumPunk" <Br***@triad.rr.com> wrote in message
news:Tl*********************@twister.southeast.rr. com...

Hi, I created an array of characters and want to convert that array to a
string.
I want to do something like this :

char array1 [25]; //with letters already in it
string string1;
string1 = array1;

That wont work will it?
Why not? C++ is easier than you think.
what would be the proper syntax? thanks in ahead!

Very slightly better is to construct the string instead of assigning to it.

char array1 [25]; //with letters already in it
string string1(array1);

I'm assuming that array1 is null terminated. If not you should write

char array1 [25]; // with 25 letters already in it
string string1(array1, 25);

john

[Shane Beasley]

"pentiumPunk" <Br***@triad.rr.com> wrote in message news:<Tl*********************@twister.southeast.rr .com>...

char array1 [25]; //with letters already in it
string string1;
string1 = array1;

That wont work will it? what would be the proper syntax? thanks in ahead!

Yes, that will work... Didn't you try it before posting here?

- Shane