How do i split a char array? (C++)

[zmp]

Hey

First of, c++ aint my primary language, just started using it (again) two weeks ago.. Anyways, i tried searching around on google for a method to split a char* and return the first word in the array.

char* test = "hello this is a test";

In C#, i would use Regex.Split(test, " ")[0] to get the first word ("hello"), but i dont know how to do that in C++.

Anyone who can help me out? ;-)

[horace1]

Hey

First of, c++ aint my primary language, just started using it (again) two weeks ago.. Anyways, i tried searching around on google for a method to split a char* and return the first word in the array.

char* test = "hello this is a test";

In C#, i would use Regex.Split(test, " ")[0] to get the first word ("hello"), but i dont know how to do that in C++.

Anyone who can help me out? ;-)

you can use a string tokenizer, see
http://www.thescripts.com/forum/thread607870.html

[lqdeffx]

strtok is the beast that you are looking for and it is used in a similar fashion. reference

[zmp]

Thanks for the quick answers :-)

I tried an example and it did work out:

int main(int argc, char *argv[])
{
    char str[] = "this is a test";
    char* test;
    test = strtok(str, " "); // Splits spaces between words in str
 
    printf ("%s\n",test); // Writes "this"
    test = strtok (NULL, " ,.-");
 
    printf("\n%i\n",sizeof(test)); // Writes 4
    system("pause");
    return 0;
}
 

However, when i try and print test[1] (which i thought would be self explainary to do), i get an error "C2664" about that i cant " convert parameter 1 from 'char' to 'const char *' ".

How do i convert it?

[horace1]

Thanks for the quick answers :-)

I tried an example and it did work out:

int main(int argc, char *argv[])
{
    char str[] = "this is a test";
    char* test;
    test = strtok(str, " "); // Splits spaces between words in str
 
    printf ("%s\n",test); // Writes "this"
    test = strtok (NULL, " ,.-");
 
    printf("\n%i\n",sizeof(test)); // Writes 4
    system("pause");
    return 0;
}
 

However, when i try and print test[1] (which i thought would be self explainary to do), i get an error "C2664" about that i cant " convert parameter 1 from 'char' to 'const char *' ".

How do i convert it?

is this what you are trying to do

    char str[] = "this is a test";
    char *test[10];
    test[0] = strtok(str, " "); // Splits spaces between words in str
    printf ("%s\n",test[0]); // Writes "this"
    test[1] = strtok (NULL, " ,.-");
    printf ("%s\n",test[1]); // Writes "is"
 

test needs to be an array of char*

[zmp]

is this what you are trying to do

    char str[] = "this is a test";
    char *test[10];
    test[0] = strtok(str, " "); // Splits spaces between words in str
    printf ("%s\n",test[0]); // Writes "this"
    test[1] = strtok (NULL, " ,.-");
    printf ("%s\n",test[1]); // Writes "is"
 

test needs to be an array of char*

yeah thats what i wanted to do, thank you :-)

This is what i ended up with:

int main(int argc, char *argv[])
{
char str[] = "this is a test";
    char *test[sizeof(strtok(str, " "))];
    if(sizeof(test) > 0)
    {
        test[0] = strtok(str, " "); // Splits spaces between words in str
        printf ("%s\n",test[0]); // Writes "this"
        for(int i = 1; i < sizeof(strtok(str, " ")); i++)
        {
            test[i] = strtok (NULL, " ,.-");
            printf ("%s\n",test[i]); // Writes "is"
        }
    }
 
    system("pause");
    return 0;
}
 

Anyways, thanks for all the replies. I appriciate that :-)