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prinf formatting problem

printf("%d", 12.0 / 8);

Why does the above print 0 and not 1.

- SSK
Mar 14 '07 #1
1 2782
horace1
1,510 Expert 1GB
printf("%d", 12.0 / 8);

Why does the above print 0 and not 1.

- SSK
the expression 12.0 / 8 yeilds a double result which you attempt to print as a int using the %d conversion specification. If you cast the result to an int it will print correctly, e.g.
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  1. printf("%d", (int) (12.0 / 8));
Mar 14 '07 #2

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