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Declaring variables in c++

105 100+
Hi all,

I have a value calculated from a member function of a class and assigned it to variable in my project say

unsigned short int var1=a.inf( ); since inf ( ) returns unsigned short int

Now I have to use this value var1 to calculate another variable var2 which should be uint64 as I have to pass this var2 to another function.

In order to make them compatible I can typecast var1,convert into uint64 and use it, but I lose the data.Could you please suggest me if there is any way to do this without typecasting and not losing any data.

Thanks.
Mar 14 '07 #1
3 1404
willakawill
1,646 1GB
Hi Perhaps you could post the code where you use a typecast and loose the data.
Mar 14 '07 #2
mickey22
105 100+
I am sorry I did not get you what u meant.
Mar 14 '07 #3
RedSon
5,000 Expert 4TB
Hi all,

I have a value calculated from a member function of a class and assigned it to variable in my project say

unsigned short int var1=a.inf( ); since inf ( ) returns unsigned short int

Now I have to use this value var1 to calculate another variable var2 which should be uint64 as I have to pass this var2 to another function.

In order to make them compatible I can typecast var1,convert into uint64 and use it, but I lose the data.Could you please suggest me if there is any way to do this without typecasting and not losing any data.

Thanks.
You say:

In order to make them compatible I can typecast var1,convert into uint64 and use it, but I lose the data.

and willakawill says:

Perhaps you could post the code where you use a typecast and loose the data?

What part of that does not make sense?
Mar 14 '07 #4

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