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What does namespace signify in C++
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Posted via http://dbforums.com
Jul 19 '05 #1
4 4536
"prasat" <me*********@dbforums.com> wrote...

What does namespace signify in C++


It signifies space for names. Names declared in a namespace
are visible inside that namespace only if you don't use any
special name resolution constructs.

Victor
Jul 19 '05 #2

"Victor Bazarov" <v.********@attAbi.com> wrote in message
news:Mu********************@rwcrnsc51.ops.asp.att. net...
"prasat" <me*********@dbforums.com> wrote...

What does namespace signify in C++

It signifies space for names. Names declared in a namespace
are visible inside that namespace only


I think you need a comma here ... <g>
if you don't use any
special name resolution constructs.

Victor

Jul 19 '05 #3
"Buster" <no***@nowhere.com> wrote...

"Victor Bazarov" <v.********@attAbi.com> wrote in message
news:Mu********************@rwcrnsc51.ops.asp.att. net...
"prasat" <me*********@dbforums.com> wrote...

What does namespace signify in C++

It signifies space for names. Names declared in a namespace
are visible inside that namespace only


I think you need a comma here ... <g>


If you want to teach English <comma> you should go to a different NG.
Here we speak and write C++ <no comma> if that's what others ask of us.
if you don't use any
special name resolution constructs.

Victor

Jul 19 '05 #4
On Tue, 19 Aug 2003 16:07:21 GMT, "Victor Bazarov"
<v.********@attAbi.com> wrote:
"Buster" <no***@nowhere.com> wrote...

"Victor Bazarov" <v.********@attAbi.com> wrote in message
news:Mu********************@rwcrnsc51.ops.asp.att. net...
> "prasat" <me*********@dbforums.com> wrote...
> >
> > What does namespace signify in C++
> >
>
> It signifies space for names. Names declared in a namespace
> are visible inside that namespace only


I think you need a comma here ... <g>


If you want to teach English <comma> you should go to a different NG.
Here we speak and write C++ <no comma> if that's what others ask of us.


Nevertheless, this statement is false:

"Names declared in a namespace
are visible inside that namespace only if you don't use any
special name resolution constructs."

Counter example:

namespace A
{
int i;
int j = ::A::i; //finds ::A::i fine.
};

Whereas this one is true, just about:

"Names declared in a namespace
are visible inside that namespace only, if you don't use any
special name resolution constructs."

or better:

"Names declared in a namespace
are visible inside that namespace only, unless you use
special name resolution constructs."

I think that's what you meant, anyway.

Tom
Jul 19 '05 #5

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