how to surround a constant with quotes?

[.rhavin grobert]

lets say i do a

#define foo AbCdEf

now i want to do *something* that is NOT

#define foo2 "AbCdEf"

but has the same effect, ... so how can i tell the preprocessor "do me
some quotes around my foo-constant"?

-.rhavin;)

[Richard Heathfield]

..rhavin grobert said:

lets say i do a

#define foo AbCdEf

now i want to do *something* that is NOT

#define foo2 "AbCdEf"

but has the same effect, ... so how can i tell the preprocessor "do me
some quotes around my foo-constant"?

I'm not exactly sure which of the FAQs you're asking, but whichever one
it is, it's answered in Section 10 of the FAQ.

--
Richard Heathfield
"Usenet is a strange place" - dmr 29/7/1999
http://www.cpax.org.uk
email: rjh at the above domain, - www.

[bytebro]

On 13 Mar, 13:57, ".rhavin grobert" <[e-mail]:

lets say i do a

#define foo AbCdEf

now i want to do *something* that is NOT

#define foo2 "AbCdEf"

but has the same effect, ... so how can i tell the preprocessor "do me
some quotes around my foo-constant"?

-.rhavin;)

#define foo(x) #x
..
..
printf (foo(Put me some quotes around this\n));
..

[santosh]

..rhavin grobert wrote:

lets say i do a

#define foo AbCdEf

now i want to do *something* that is NOT

#define foo2 "AbCdEf"

but has the same effect, ... so how can i tell the preprocessor "do me
some quotes around my foo-constant"?

Yes.

#define foo(x) #x

What's wrong with the above solution for what you're trying to do?

[pete]

..rhavin grobert wrote:

>
lets say i do a

#define foo AbCdEf

now i want to do *something* that is NOT

#define foo2 "AbCdEf"

but has the same effect, ... so how can i tell the preprocessor "do me
some quotes around my foo-constant"?

/* BEGIN new.c */

#include <stdio.h>

#define foo AbCdEf
#define str(x) # x
#define xstr(x) str(x)

int main(void)
{
puts(xstr(foo));
return 0;
}

/* END new.c */

--
pete

[Old Wolf]

On Mar 14, 3:59 am, "santosh" <[e-mail]:

.rhavin grobert wrote:

lets say i do a
#define foo AbCdEf
now i want to do *something* that is NOT
#define foo2 "AbCdEf"

but has the same effect,

#define foo(x) #x

What's wrong with the above solution for what you're trying to do?

Well, he would need to do it in several stages:
#define BAR(x) #x
#define BAZ(x) BAR(x)
#define foo2 BAZ(foo)