473,385 Members | 1,814 Online
Bytes | Software Development & Data Engineering Community
Post Job

Home Posts Topics Members FAQ

Join Bytes to post your question to a community of 473,385 software developers and data experts.

Question about usage of pointer in trees, linked list (The double indirection)

When implementing Linked list, stack, or trees, we always use pointers
to 'link' the nodes.
And every node is always defined as:
struct node
{
type data; //data this node contains
...
node * nPtr; //the next node's pointer
}

And we also define operations as insert, delete, etc. on the data
structure.
MY QUESTION IS:
why we always pass node**(pointer to the pointer to the node) as
argument to these operations? Why we can not just use the node *?

Thank you!

Ji

Mar 10 '07 #1
9 2810
william wrote:
When implementing Linked list, stack, or trees, we always use pointers
to 'link' the nodes.
And every node is always defined as:
struct node
{
type data; //data this node contains
...
node * nPtr; //the next node's pointer
}

And we also define operations as insert, delete, etc. on the data
structure.
MY QUESTION IS:
why we always pass node**(pointer to the pointer to the node) as
argument to these operations? Why we can not just use the node *?
So the value of the pointer can be changed, as well as the value the
pointer point to.

--
Ian Collins.
Mar 10 '07 #2
william wrote:
When implementing Linked list, stack, or trees, we always use pointers
to 'link' the nodes.
And every node is always defined as:
struct node
{
type data; //data this node contains
...
node * nPtr; //the next node's pointer
}

And we also define operations as insert, delete, etc. on the data
structure.
MY QUESTION IS:
why we always pass node**(pointer to the pointer to the node) as
argument to these operations? Why we can not just use the node *?

Thank you!

Ji
In a good implementation of a linked list, the nodes are completely
hidden. You would never pass node* or node** to any operations.

What you are looking at is a bad implementation of a linked list. I
can't tell you why it uses node** or node* without seeing the code. It
shouldn't use either.

john
Mar 10 '07 #3
On Mar 10, 3:48 pm, John Harrison <john_androni...@hotmail.comwrote:
william wrote:
When implementing Linked list, stack, or trees, we always use pointers
to 'link' the nodes.
And every node is always defined as:
struct node
{
type data; //data this node contains
...
node * nPtr; //the next node's pointer
}
And we also define operations as insert, delete, etc. on the data
structure.
MY QUESTION IS:
why we always pass node**(pointer to the pointer to the node) as
argument to these operations? Why we can not just use the node *?
Thank you!
Ji

In a good implementation of a linked list, the nodes are completely
hidden. You would never pass node* or node** to any operations.
What does it mean by nodes are completely hidden(as being refered to,
nodes means the pointers to the actual struct block in memory, or the
structs themselves?)
>
What you are looking at is a bad implementation of a linked list. I
can't tell you why it uses node** or node* without seeing the code. It
shouldn't use either.

john
I paste the sample code below, which came from the book 'C how to
program'. John, could you please offer me a good example of
implementation of linked list? Thank you.

************************************************** ********************
#include <stdio.h>
#include <stdlib.h>

struct listNode
{
char data;
struct listNode *nextPtr;
};

typedef struct listNode ListNode;
typedef ListNode *ListNodePtr;

void insert(ListNodePtr *, char);
char delete(ListNodePtr *, char);
int isEmpty(ListNodePtr);
void printList(ListNodePtr);
void instructions(void);

int main()
{
ListNodePtr startPtr=NULL;
int choice;
char item;

instructions(); //display the menu;
printf(">");
scanf("%d",&choice);

while(choice!=3)
{
switch (choice)
{
case 1:
printf("Enter a character: ");
scanf("\n%c",&item);
insert(&startPtr,item);
printList(startPtr);
break;

case 2:
if(!isEmpty(startPtr))
{
printf("Enter character to be deleted: ");
scanf("\n%c",&item);

if(delete(&startPtr,item))
{
printf("%c deleted.\n",item);
printList(startPtr);
}
else
printf("%c not found.\n\n",item);
}
else
printf("List is empty.\n\n");
break;
default:
printf("Invalid choice.\n\n");
instructions();
break;
}
printf(">");
scanf("%d",&choice);
}
printf("End of run.\n");
return 0;
}

void instructions(void)
{
printf("Enter your choice:\n");
printf("1 to insert an element into the list.\n"
"2 to delete an element from the list.\n"
"3 to exit the program.\n");
}

void insert(ListNodePtr *sPtr, char value)
{
ListNodePtr newPtr, previousPtr, currentPtr;

newPtr=malloc(sizeof(ListNode));
if(newPtr !=NULL)
{
newPtr->data=value;
newPtr->nextPtr=NULL;

//set the searching index(previousPtr and
//currentPtr)to the start of the list.
previousPtr=NULL;
currentPtr=*sPtr;

while(currentPtr !=NULL && value>currentPtr->data)
{
previousPtr=currentPtr;
currentPtr=currentPtr->nextPtr;
} //keep going

if(previousPtr==NULL)
{
newPtr->nextPtr=*sPtr;
*sPtr=newPtr;//insert the node at the beginning of the list
}
else
{
previousPtr->nextPtr=newPtr;
newPtr->nextPtr=currentPtr;
}
}
else
{
printf("%c not inserted. No memory available.\n",value);
}
}

char delete(ListNodePtr *sPtr, char value)
{
ListNodePtr previousPtr,currentPtr,tempPtr;

if (value==(*sPtr)->data)
{
tempPtr=*sPtr;
*sPtr=(*sPtr)->nextPtr;
free(tempPtr);
return value;
}
else
{
previousPtr=*sPtr;
currentPtr=(*sPtr)->nextPtr;//setup the cursor at the beginning

//when the cursor didn't reach the tail and cursor didn't find the
//specified value, the cursor keep going along the list
while(currentPtr !=NULL && currentPtr->data !=value)
{
previousPtr=currentPtr;
currentPtr=currentPtr->nextPtr;//move on to next node
}

if(currentPtr !=NULL)//if not reaching the tail
{
tempPtr=currentPtr;
previousPtr->nextPtr=currentPtr->nextPtr;
free(tempPtr);
return value;
}
}
return '\0';//return null char;
}

int isEmpty(ListNodePtr sPtr)
{
return sPtr==NULL;
}

void printList(ListNodePtr currentPtr)
{
if(currentPtr==NULL)
{
printf("List is Empty.\n\n");
}
else
{
printf("The list is:\n");
while(currentPtr !=NULL)
{
printf("%c--",currentPtr->data);
currentPtr=currentPtr->nextPtr;
}
printf("NULL\n\n");
}

}
************************************************** **************
Mar 10 '07 #4
On Mar 10, 4:44 pm, "william" <william.m...@gmail.comwrote:
On Mar 10, 3:48 pm, John Harrison <john_androni...@hotmail.comwrote:
william wrote:
When implementing Linked list, stack, or trees, we always use pointers
to 'link' the nodes.
And every node is always defined as:
struct node
{
type data; //data this node contains
...
node * nPtr; //the next node's pointer
}
And we also define operations as insert, delete, etc. on the data
structure.
MY QUESTION IS:
why we always pass node**(pointer to the pointer to the node) as
argument to these operations? Why we can not just use the node *?
Thank you!
Ji
In a good implementation of a linked list, the nodes are completely
hidden. You would never pass node* or node** to any operations.

What does it mean by nodes are completely hidden(as being refered to,
nodes means the pointers to the actual struct block in memory, or the
structs themselves?)
What you are looking at is a bad implementation of a linked list. I
can't tell you why it uses node** or node* without seeing the code. It
shouldn't use either.
john

I paste the sample code below, which came from the book 'C how to
program'. John, could you please offer me a good example of
implementation of linked list? Thank you.

************************************************** ********************
#include <stdio.h>
#include <stdlib.h>

struct listNode
{
char data;
struct listNode *nextPtr;

};

typedef struct listNode ListNode;
typedef ListNode *ListNodePtr;

void insert(ListNodePtr *, char);
char delete(ListNodePtr *, char);
int isEmpty(ListNodePtr);
void printList(ListNodePtr);
void instructions(void);

int main()
{
ListNodePtr startPtr=NULL;
int choice;
char item;

instructions(); //display the menu;
printf(">");
scanf("%d",&choice);

while(choice!=3)
{
switch (choice)
{
case 1:
printf("Enter a character: ");
scanf("\n%c",&item);
insert(&startPtr,item);
printList(startPtr);
break;

case 2:
if(!isEmpty(startPtr))
{
printf("Enter character to be deleted: ");
scanf("\n%c",&item);

if(delete(&startPtr,item))
{
printf("%c deleted.\n",item);
printList(startPtr);
}
else
printf("%c not found.\n\n",item);
}
else
printf("List is empty.\n\n");
break;
default:
printf("Invalid choice.\n\n");
instructions();
break;
}
printf(">");
scanf("%d",&choice);
}
printf("End of run.\n");
return 0;

}

void instructions(void)
{
printf("Enter your choice:\n");
printf("1 to insert an element into the list.\n"
"2 to delete an element from the list.\n"
"3 to exit the program.\n");

}

void insert(ListNodePtr *sPtr, char value)
{
ListNodePtr newPtr, previousPtr, currentPtr;

newPtr=malloc(sizeof(ListNode));
if(newPtr !=NULL)
{
newPtr->data=value;
newPtr->nextPtr=NULL;

//set the searching index(previousPtr and
//currentPtr)to the start of the list.
previousPtr=NULL;
currentPtr=*sPtr;

while(currentPtr !=NULL && value>currentPtr->data)
{
previousPtr=currentPtr;
currentPtr=currentPtr->nextPtr;
} //keep going

if(previousPtr==NULL)
{
newPtr->nextPtr=*sPtr;
*sPtr=newPtr;//insert the node at the beginning of the list
}
else
{
previousPtr->nextPtr=newPtr;
newPtr->nextPtr=currentPtr;
}
}
else
{
printf("%c not inserted. No memory available.\n",value);
}

}

char delete(ListNodePtr *sPtr, char value)
{
ListNodePtr previousPtr,currentPtr,tempPtr;

if (value==(*sPtr)->data)
{
tempPtr=*sPtr;
*sPtr=(*sPtr)->nextPtr;
free(tempPtr);
return value;
}
else
{
previousPtr=*sPtr;
currentPtr=(*sPtr)->nextPtr;//setup the cursor at the beginning

//when the cursor didn't reach the tail and cursor didn't find the
//specified value, the cursor keep going along the list
while(currentPtr !=NULL && currentPtr->data !=value)
{
previousPtr=currentPtr;
currentPtr=currentPtr->nextPtr;//move on to next node
}

if(currentPtr !=NULL)//if not reaching the tail
{
tempPtr=currentPtr;
previousPtr->nextPtr=currentPtr->nextPtr;
free(tempPtr);
return value;
}
}
return '\0';//return null char;

}

int isEmpty(ListNodePtr sPtr)
{
return sPtr==NULL;

}

void printList(ListNodePtr currentPtr)
{
if(currentPtr==NULL)
{
printf("List is Empty.\n\n");
}
else
{
printf("The list is:\n");
while(currentPtr !=NULL)
{
printf("%c--",currentPtr->data);
currentPtr=currentPtr->nextPtr;
}
printf("NULL\n\n");
}

}

************************************************** **************
Above is all the code.

here is the segment that confuses me:

in 'main':
ListNodePtr startPtr=NULL;
....
....
insert(&startPtr,item);
....
And the prototype of 'insert' is:
void insert(ListNodePtr *, char);
// you can find the content in the code segment I posted just now.

So, is there any CONVENTION that how programmers implement different
data structure:
LINKED LIST
TREE
QUEQUE
STACK
and define operations on those data structure?

Where can I find a good resource talking about this?

Mar 10 '07 #5
william wrote:
>
Above is all the code.

here is the segment that confuses me:

in 'main':
ListNodePtr startPtr=NULL;
....
....
insert(&startPtr,item);
....
And the prototype of 'insert' is:
void insert(ListNodePtr *, char);
What part of this confuses you? If insert didn't take the address of
startPtr, how could it change it?

--
Ian Collins.
Mar 10 '07 #6
>
>
I paste the sample code below, which came from the book 'C how to
program'. John, could you please offer me a good example of
implementation of linked list? Thank you.
I didn't realise you were programming in C. C and C++ are different
languages, what is good in C not the same as what is good in C++.

The code below is probably fine in C, but it wouldn't be good C++. In
C++ it's much easier to seperate the interface from the implementation.

If you haven't got your answer already (Ian has given you the answer)
you should probably ask questions about this code on comp.lang.c, it's C
not C++.

john
Mar 10 '07 #7
william wrote:
[snip]
So, is there any CONVENTION that how programmers implement different
data structure:
LINKED LIST
TREE
QUEQUE
STACK
and define operations on those data structure?
Yes, there is: you don't implement them yourself, you use the standard
library instead. It provides (among other things):

std::list
std::queue
std::stack

and for problems involving search trees:

std::set, std::multiset
std::map, std::multimap

Where can I find a good resource talking about this?
Any introduction to the standard library should cover the standard container
classes and adaptors.
Best

Kai-Uwe Bux
Mar 10 '07 #8
On Mar 10, 5:00 pm, Ian Collins <ian-n...@hotmail.comwrote:
william wrote:
Above is all the code.
here is the segment that confuses me:
in 'main':
ListNodePtr startPtr=NULL;
....
....
insert(&startPtr,item);
....
And the prototype of 'insert' is:
void insert(ListNodePtr *, char);

What part of this confuses you? If insert didn't take the address of
startPtr, how could it change it?
Thank you Ian, I understand it now. The whole structure is a
pointer(to the starting struct), so we need to change it if we insert
a new node at the beginning, right?
--
Ian Collins.

Mar 10 '07 #9
On Mar 10, 5:09 pm, Kai-Uwe Bux <jkherci...@gmx.netwrote:
william wrote:

[snip]
So, is there any CONVENTION that how programmers implement different
data structure:
LINKED LIST
TREE
QUEQUE
STACK
and define operations on those data structure?

Yes, there is: you don't implement them yourself, you use the standard
library instead. It provides (among other things):

std::list
std::queue
std::stack

and for problems involving search trees:

std::set, std::multiset
std::map, std::multimap
Where can I find a good resource talking about this?

Any introduction to the standard library should cover the standard container
classes and adaptors.

Best

Kai-Uwe Bux
Thank you for your reply! I got it.

regards

Ji

Mar 10 '07 #10

This thread has been closed and replies have been disabled. Please start a new discussion.

Similar topics

9
by: kazio | last post by:
Hello, So, I need to have double linked, circular list (last element point to the first one and first one points to the last one). I thought maybe I could use list container from STL, but...
5
by: John N. | last post by:
Hi All, Here I have a linked list each containing a char and is double linked. Then I have a pointer to an item in that list which is the current insertion point. In this funtion, the user...
11
by: theshowmecanuck | last post by:
As a matter of academic interest only, is there a way to programmatically list the 'c' data types? I am not looking for detail, just if it is possible, and what function could be used to...
4
by: JS | last post by:
I have a file called test.c. There I create a pointer to a pcb struct: struct pcb {   void *(*start_routine) (void *);   void *arg;   jmp_buf state;   int    stack; }; ...
204
by: Alexei A. Frounze | last post by:
Hi all, I have a question regarding the gcc behavior (gcc version 3.3.4). On the following test program it emits a warning: #include <stdio.h> int aInt2 = {0,1,2,4,9,16}; int aInt3 =...
10
by: Bonj | last post by:
I almost understand TSTs, to the point where I just need to know the answer to this: When making a TST (in C++) that will have as its leaf nodes words that make up SQL language and an categorising...
7
by: | last post by:
Hi, From 11.11 here, I know that member objects get their dtor's called autmatically: http://www.parashift.com/c++-faq-lite/dtors.html#faq-11.11 What if I have a pointer to a member object?...
24
by: Kavya | last post by:
int main (){ int a={{1,2,3},{4,5,6}}; int (*ptr)=a; /* This should be fine and give 3 as output*/ printf("%d\n",(*ptr)); ++ptr;
8
by: =?ISO-8859-1?Q?Konrad_M=FChler?= | last post by:
Hi, I've a list of objects. I iterate the list and read the value of each object for many operation like: x = myList.value1 + myList.value2 etc. My question: Is it efficient to always use...
0
isladogs
by: isladogs | last post by:
The next Access Europe User Group meeting will be on Wednesday 3 Apr 2024 starting at 18:00 UK time (6PM UTC+1) and finishing by 19:30 (7.30PM). In this session, we are pleased to welcome former...
0
by: taylorcarr | last post by:
A Canon printer is a smart device known for being advanced, efficient, and reliable. It is designed for home, office, and hybrid workspace use and can also be used for a variety of purposes. However,...
0
by: Charles Arthur | last post by:
How do i turn on java script on a villaon, callus and itel keypad mobile phone
0
by: aa123db | last post by:
Variable and constants Use var or let for variables and const fror constants. Var foo ='bar'; Let foo ='bar';const baz ='bar'; Functions function $name$ ($parameters$) { } ...
0
by: ryjfgjl | last post by:
In our work, we often receive Excel tables with data in the same format. If we want to analyze these data, it can be difficult to analyze them because the data is spread across multiple Excel files...
0
by: emmanuelkatto | last post by:
Hi All, I am Emmanuel katto from Uganda. I want to ask what challenges you've faced while migrating a website to cloud. Please let me know. Thanks! Emmanuel
0
BarryA
by: BarryA | last post by:
What are the essential steps and strategies outlined in the Data Structures and Algorithms (DSA) roadmap for aspiring data scientists? How can individuals effectively utilize this roadmap to progress...
1
by: Sonnysonu | last post by:
This is the data of csv file 1 2 3 1 2 3 1 2 3 1 2 3 2 3 2 3 3 the lengths should be different i have to store the data by column-wise with in the specific length. suppose the i have to...
0
by: Hystou | last post by:
There are some requirements for setting up RAID: 1. The motherboard and BIOS support RAID configuration. 2. The motherboard has 2 or more available SATA protocol SSD/HDD slots (including MSATA, M.2...

By using Bytes.com and it's services, you agree to our Privacy Policy and Terms of Use.

To disable or enable advertisements and analytics tracking please visit the manage ads & tracking page.