Syntax error on #define

[Anshul]

Hi,

I tried compiling this code -

int main()
{
char abc[10] = "%s";
printf("\033[1m" abc "\033[m" , "doing");
}

with gcc version 2.96. I get this error message -

parse error before `abc'

Please explain, whats wrong here. The intention is to print a string
in bold characters on the screen.

Thanks,
Anshul

[Anshul]

Oops, bad subject line.

Thanks,
Anshul

[santosh]

Anshul wrote:

Hi,

I tried compiling this code -

int main()
{
char abc[10] = "%s";
printf("\033[1m" abc "\033[m" , "doing");

Only adjacent string literals are concactenated. The expression abc is
not a string literal, but a pointer constant value.

Try:

printf("\033[1m", " %s ", "\033[m\n", "doing");

[Joachim Schmitz]

"Anshul" <an******@gmail.comschrieb im Newsbeitrag
news:11**********************@30g2000cwc.googlegro ups.com...

Hi,

I tried compiling this code -

#include <stdio.h>

int main()
{
char abc[10] = "%s";
printf("\033[1m" abc "\033[m" , "doing");

printf("\033[1m%s\033[m" , "doing");
fflush(stdout);
return 0;

}

with gcc version 2.96. I get this error message -

parse error before `abc'

Please explain, whats wrong here. The intention is to print a string
in bold characters on the screen.

Thanks,
Anshul

Bye, Jojo

[Joachim Schmitz]

"santosh" <sa*********@gmail.comschrieb im Newsbeitrag
news:11*********************@s48g2000cws.googlegro ups.com...

Anshul wrote:

>Hi,

I tried compiling this code -

int main()
{
char abc[10] = "%s";
printf("\033[1m" abc "\033[m" , "doing");

Only adjacent string literals are concactenated. The expression abc is
not a string literal, but a pointer constant value.

Try:

printf("\033[1m", " %s ", "\033[m\n", "doing");

Still doesn't work, got to be:
printf("\033[1m%s\033[m\n", "doing");

Bye, Jojo

[Richard Heathfield]

santosh said:

Anshul wrote:

>Hi,

I tried compiling this code -

int main()
{
char abc[10] = "%s";
printf("\033[1m" abc "\033[m" , "doing");

Only adjacent string literals are concactenated. The expression abc is
not a string literal, but a pointer constant value.

Try:

printf("\033[1m", " %s ", "\033[m\n", "doing");

Er, no. :-)

printf("\033[1m%s\033[m\n", "doing");

or even just:

printf("\033[1mdoing\033[m\n");

(although the former version is perhaps slightly more maintainable, in
that it's easier to see what needs changing when the need arises).

--
Richard Heathfield
"Usenet is a strange place" - dmr 29/7/1999
http://www.cpax.org.uk
email: rjh at the above domain, - www.

[Richard Tobin]

In article <11*********************@s48g2000cws.googlegroups. com>,
santosh <sa*********@gmail.comwrote:

>Only adjacent string literals are concactenated. The expression abc is
not a string literal, but a pointer constant value.

Try:

printf("\033[1m", " %s ", "\033[m\n", "doing");

^ ^

Take out those commas!

-- Richard

--
"Consideration shall be given to the need for as many as 32 characters
in some alphabets" - X3.4, 1963.

[santosh]

santosh wrote:

Anshul wrote:

Hi,

I tried compiling this code -

int main()
{
char abc[10] = "%s";
printf("\033[1m" abc "\033[m" , "doing");

Only adjacent string literals are concactenated. The expression abc is
not a string literal, but a pointer constant value.

Try:

printf("\033[1m", " %s ", "\033[m\n", "doing");

Sorry to all about this. It should be:

printf("\033[1m" "%s" "\033[m\n", "doing");

or better yet, versions that Richard, Richard and Joachim posted.

[Dik T. Winter]

In article <j2***************@news.cpqcorp.net"Joachim Schmitz" <no************@hp.comwrites:

"santosh" <sa*********@gmail.comschrieb im Newsbeitrag
news:11*********************@s48g2000cws.googlegro ups.com...

Anshul wrote:

Hi,

I tried compiling this code -

int main()
{
char abc[10] = "%s";
printf("\033[1m" abc "\033[m" , "doing");

Only adjacent string literals are concactenated. The expression abc is
not a string literal, but a pointer constant value.

Try:

printf("\033[1m", " %s ", "\033[m\n", "doing");

Eh, no. But the following *will* work:
#define abc "%s"
printf("\033[1m" abc "\033[m", "doing");
--
dik t. winter, cwi, kruislaan 413, 1098 sj amsterdam, nederland, [phone]
home: bovenover 215, 1025 jn amsterdam, nederland; http://www.cwi.nl/~dik/