a small pointer help

[jijophilip]

write a c++ program using Object Oriented Programming
to accept Customer Code No , Customer Name and Total Bill Amount
of (n) number of customer
n is accepted at runtime



Also after accepting print the data as per format given below

Customer

Code No Name Total Bill Amount
----------------------------------------------------------------




----------------------------------------------------------------
Grand Total

Print the Grand total in word format as

If Grand total is 8769
Print as EIGHT SEVEN SIX NINE



till now i have done the following code but i am struck with the looping where i have to take n users...
if anyone can plz modify he code and tell me...

class customer
{
private:
    int ncust;
    int *codeno;
    char **name;
    int *tbill;
    char name[20];
    int grandttl;
 
public:
    void ct_accept (void);
    void ct_print (void);
};
//Function
 
#include<iostream.h>
#include<string.h>
#include <iomanip.h>
 
 
 
void customer::ct_accept(void)
{
    cout<<"Enter Customer Code no.: ";
    cin>>codeno;cin.get();
    cout<<"Enter Customer Name: ";
    cin.getline(name,20);
    cout<<"Enter Customer Grand Total: ";
    cin>>grandttl;
}
 
void customer::ct_print(void)
{
    /*int num;
    cout<<"Enter the Number of Customers: ";
    cin>>num;*/
 
    cout<<endl << "Customer Code No. ";
    cout<<"Customer Name                 ";
    cout<<"Grand Total      ";
    cout << endl;
    for(int i=0;i<=62;i++)
    {
        cout<<"-";
    }
    cout<<endl;
 
    cout<<setw(10) << codeno;
    cout<<setw(30) << name;
    cout<<setw(20) << grandttl;
    cout<<endl;
 
    for(i=0;i<=62;i++)
    {
        cout<<"-";
    }
cout<<endl;
cout<<"Grand Total: ";    
int word,rem, store[100000];
if(grandttl==0)
{
    cout<<"zero";
}
else
{
 
    while(word!=0)
    {
    word=grandttl/10;
    rem=grandttl%10;
 
    store[i]=rem;
    i++;
    grandttl=word;    
    }    
 
i--;
for(i;i>=0;i--)
{
    store[i];    
 
switch(store[i])
        {
        case 0:
        cout<<"zero ";
        break;
 
        case 1:
        cout<<"one ";
        break;
 
        case 2:
        cout<<"two ";
        break;
 
        case 3:
        cout<<"three ";
        break;
 
        case 4:
        cout<<"four ";
        break;
 
        case 5:
        cout<<"five ";
        break;
 
        case 6:
        cout<<"six ";
        break;
 
        case 7:
        cout<<"seven ";
        break;
 
        case 8:
        cout<<"eight ";
        break;
 
        case 9:
        cout<<"nine ";
        break;
 
        }
 
 
}
 
}    
}
 
 
main()
{
    customer rec;
    rec.ct_accept();
    rec.ct_print();
    cin.get();
    cin.get();
    return 0;
}

[DeMan]

The code is a little difficult without "code" tags, however I think (if I understand what you ask) that you would want to change the for loop to loop while i<= num (that is, the number of customers the user entered)

[horace1]

couple of immediate things to notice

class customer
{
private:
    int ncust;
    int *codeno;      <<<   why is this a pointer
    char **name;      <<  definintion of name
    int *tbill;
    char name[20];   ,,  definition of name
    int grandttl;
 
 

should variable codeno be a pointer ? - you read it as an int in

void customer::ct_accept(void)
{
    cout<<"Enter Customer Code no.: ";
    cin>>codeno;cin.get();
 

you have variable name defined twice!