Simple Bitwise C/C++ operator function

[philips217]

Hi,
I have two seperate unsigned longs and want to add one infront of the other.
baicaully something like:
unsigned long one;
unsigned long two;
unsigned long long add;

where say: one = 1001000011110010111011100101; //28 binary = 151989989
and two = 11111101000011100011111111100001;//32 binary = 4245569505
and I want
add = 10010000111100101110111001011111110100001110001111 1111100001
(add = |one|two| )

Is there a function for this? or can anyone help me do this? (There must be an easy way I just can't think of any because strtoul() only goes as high as unsigned longs and not unsigned long longs.)

Thanks.

[bravephantom]

better to use them as characters unless u dont need them in any arithmatic operations.
define 2 arrays of type (char)
> then use a loop that reads characters (use the instruction: getchar)
> in each iteration, check if the it reads the symbol or not the end yet
> when u get the symbol, switch to the other variable with another array
> Merge arrays in one array
> get one char. from the first array and put it in a separate array
> when u reach the end of the array, move to the second array and add it to the new one
*> now u got 1 array with all 1s and 0s
************************************************** *****************************************
maybe there is another way without using 2 arrays at first

[lqdeffx]

I agree, can't think of any functions off hand that could merge numeric types. might be easier & safer though to convert to a C++ string, or at least it would be easier for me. one way to convert then just do a strcat() and its all good.

[philips217]

Thanks a lot guys.

I actaully did:
add = binOne;
add = add << 32;
add = add + binTwo;

and it worked great. I thought for some reason << 32 would just push the bits off the end but it adds 0's so it worked awesome.

ex: I thought
binOne = 1101
binOne << 3 would then = 1000 (getting rid of the 110)
but it really equals 1101000

Thanks!