increment in if statement

[Nishu]

Hi All,

My Aim here is to increment lArray whether control goes inside if
statement or not. Is this a portable step and C guarantees that lArray
must be incremented?

Thanks,
Nishu
#include<stdio.h>

int main(void)
{
int i = 7;
int array[] = {0,1,1,0,1,1,0};
int* lArray;

lArray = array;

while(i--)
{
if(*lArray++) /* Is this a portable step? */
{
printf("enters in if loop\n");
}
}
return 0;

}

[Danny]

On Mar 1, 9:50 am, "Nishu" <[e-mail]:

Hi All,

My Aim here is to increment lArray whether control goes inside if
statement or not. Is this a portable step and C guarantees that lArray
must be incremented?

Thanks,
Nishu

#include<stdio.h>

int main(void)
{
int i = 7;
int array[] = {0,1,1,0,1,1,0};
int* lArray;

lArray = array;

while(i--)
{
if(*lArray++) /* Is this a portable step? */
{
printf("enters in if loop\n");
}
}
return 0;

}

Yes. As far as I know, you're safe.

[Flash Gordon]

Nishu wrote, On 01/03/07 07:50:

Hi All,

My Aim here is to increment lArray whether control goes inside if
statement or not. Is this a portable step and C guarantees that lArray
must be incremented?

#include<stdio.h>

int main(void)
{
int i = 7;
int array[] = {0,1,1,0,1,1,0};

Apart from the fact I would not write code like this, I would rearrange
the above two declarations to
int array[] = {0,1,1,0,1,1,0};
int i = (sizeof array) / sizeof *array;
Then you don't have to change the initialisation of i if you change the
size of the array.

int* lArray;

lArray = array;

while(i--)
{
if(*lArray++) /* Is this a portable step? */

Yes, it is completely portable, and almost equivalent to:
lArray++;
if (*(lArray-1))

I say almost because of sequence points which would be more important
with a more complex expression.

{
printf("enters in if loop\n");
}
}
return 0;

}

--
Flash Gordon