computer problem...

[Bigj0410]

i was working on a couple program questions and apparently...my PC has a virus....so right now i'm on a friends PC where he doesn't have any C++ programs....so i was just wondering what are the outputs of these programs below...thx in advance ;)

(program 1)

char x[3] = {‘0’, ‘1’, ‘2’} ;
int y[3];
for (int i = 0 ; i < 3 ; i++)
{
y[i] = x[i] ;
cout << x[i] << "\t" <<y[i]<< endl;
}

(program 2)

#include <iostream>
using namespace std;
long int mystery(int, int);
int main()
{
int in1, in2;
cout << "Enter two integers: ";
cin>>in1>>in2;
cout <<"The result is " << mystery (in1, in2)<<endl;
return 0;
}
//parameter b must be a positive
long int mystery (int a, int b)
{
if (b==1)
return a;
else
return a + product(a, b-1);
}

[DeMan]

Surely the idea is for you to step through the code and try to see if you can see what's going on?

The first one is very simple, have a think about what is being done. (The cout line is the one that does the printing./.....)

the key here is to follow the code through the method calls. I am assuming that product(int, int) is defined somewhere?......

[Bigj0410]

Surely the idea is for you to step through the code and try to see if you can see what's going on?

The first one is very simple, have a think about what is being done. (The cout line is the one that does the printing./.....)

the key here is to follow the code through the method calls. I am assuming that product(int, int) is defined somewhere?......

yea...but i don't know where though

[Ganon11]

I have a feeling that the function call is supposed to be mystery(a, b-1) rather than product(a, b-1).

[Bigj0410]

I have a feeling that the function call is supposed to be mystery(a, b-1) rather than product(a, b-1).

...ok....right now my PC is getting checked...thx 4 da info

[Bigj0410]

ok...now it works