cout string problem

[Gary Wessle]

Hi
could some one please look at this and tell me why it is printing out
what it is.
all what I am trying to do is print out 105 of "-".

std::string s = string("-", 105 );
std::cout << s << std::endl;

out:
-%d-%d-%d %d:%d:%d8%G���%@X&%G�� %@x>%G���%@R%G��￠½Ã¯Â¿Â½Ã¯Â¿Â½Ã¯Â¿Â½Ã¯Â¿Â½Ã¯Â¿Â½Ã¯Â¿Â½Ã¯Â¿Â½%@zPL %G�%@
thanks

[Piyo]

I always thought that the std::string constructor looked like this:

string(size_type n, const T& t)

this would mean, you should do this instead:

// note, size goes first and
// const T is char not a string (ie. not "-")
std::string s( 105, '-' );

Hope that works for you.

Gary Wessle wrote:

Hi
could some one please look at this and tell me why it is printing out
what it is.
all what I am trying to do is print out 105 of "-".

std::string s = string("-", 105 );
std::cout << s << std::endl;

out:
-%d-%d-%d %d:%d:%d8%G���%@X&%G�� %@x>%G���%@R%G��￠½Ã¯Â¿Â½Ã¯Â¿Â½Ã¯Â¿Â½Ã¯Â¿Â½Ã¯Â¿Â½Ã¯Â¿Â½Ã¯Â¿Â½%@zPL %G�%@
thanks

[Mike Wahler]

"Gary Wessle" <ph****@yahoo.comwrote in message
news:m3************@localhost.localdomain...

>
Hi
could some one please look at this and tell me why it is printing out
what it is.
all what I am trying to do is print out 105 of "-".

std::string s = string("-", 105 );
std::cout << s << std::endl;

out:
-%d-%d-%d
%d:%d:%d8%G���%@X&%G��%@x>%Gï¿½ï¿½ï ¿½%@R%G����������%@zPL%Gï¿ ½%@
thanks

#include <iostream>
#include <string>

int main()
{
std::cout << std::string(105, '-') << '\n';
return 0;
}

-Mike

[Old Wolf]

On Feb 19, 2:20 pm, Gary Wessle <[e-mail]:

>
std::string s = string("-", 105 );
std::cout << s << std::endl;

This creates a string of length 105, using the character
pointed to by the pointer in the first parameter, and
the 104 subsequent characters in memory.

out:
-%d-%d-%d %d:%d:%d8%G���%@X&%G��%@x>%Gï¿½ï¿½ï ¿½%@R%G����������%@zPL%Gï¿ ½%@

Looks about right :)