void __fastcall TRabatyForm::Edit1iKeyPress(TObject *Sender, char &Key)
{
if((Key < '0') (Key > '9') Key = '#0';
}
Why? I need to filter alloed key do digits only.
Pawel
5  1793 
On Mon, 14 Jul 2003 09:51:42 +0200, "Paweł" <ko*****@poczta.onet.pl> wrote: void __fastcall TRabatyForm::Edit1iKeyPress(TObject *Sender, char &Key)
Note that "__fastcall" is not standard C++.
{
if((Key < '0') (Key > '9') Key = '#0';
1. You need an operator between the two expressions.
Probably you meant "||".
2. Specifying more than one character between apostrophes
like in '#0' is an old C syntax for "magic" integer
values, but there isn't room in a char for that value.
Probably you meant something else. Like '\0'.
}
Why? I need to filter alloed key do digits only.
Have you considered 'isdigit'?
> Note that "__fastcall" is not standard C++.
{
if((Key < '0') (Key > '9') Key = '#0';
1. You need an operator between the two expressions.
Probably you meant "||".
yes, but i tried word " or " and there was an compile error
2. Specifying more than one character between apostrophes
like in '#0' is an old C syntax for "magic" integer
values, but there isn't room in a char for that value.
Probably you meant something else. Like '\0'.
U R right.}
Why? I need to filter alloed key do digits only.
Have you considered 'isdigit'?
This helped. Thx.
Pawel
On Mon, 14 Jul 2003 10:36:03 +0200, "Paweł" <ko*****@poczta.onet.pl> wrote: Note that "__fastcall" is not standard C++.
>{
> if((Key < '0') (Key > '9') Key = '#0';
1. You need an operator between the two expressions.
Probably you meant "||".
yes, but i tried word " or " and there was an compile error
2. Specifying more than one character between apostrophes
like in '#0' is an old C syntax for "magic" integer
values, but there isn't room in a char for that value.
Probably you meant something else. Like '\0'.
U R right. >}
>
>Why? I need to filter alloed key do digits only.
Have you considered 'isdigit'?
This helped. Thx.
You're welcome. Aside from C++ programming, the most common
error/oversight in doing what you're attempting is to forget
about _pasting_ of text into the control... Just a hint.
"Jeremy Cowles" <je*************************@asifl.com> wrote... "Paweł" <ko*****@poczta.onet.pl> wrote in message
news:be**********@news.onet.pl... Note that "__fastcall" is not standard C++.
>{
> if((Key < '0') (Key > '9') Key = '#0';
There is a missing closing parenthesis after '9'.
1. You need an operator between the two expressions.
Probably you meant "||".
yes, but i tried word " or " and there was an compile error
AFAIK, keyword "Or" is not valid in C++ as a boolean operator (or any
other operator for that matter).
You know wrong. "or", "and", "xor", "not" "not_eq", "and_eq",
"compl", "bitor", "bitand", "xor_eq", "or_eq", are reserved as
_alternative_ tokens for "||", "&&" , "^", "!", "!=", "&=",
"~", "|", "&", "^=", "|=", respectively.
If a compiler does not accept those, it's non-compliant.
Victor
"Victor Bazarov" <v.********@attAbi.com> wrote in message
news:vh************@corp.supernews.com... "Jeremy Cowles" <je*************************@asifl.com> wrote... "Paweł" <ko*****@poczta.onet.pl> wrote in message
news:be**********@news.onet.pl...
[snip]
yes, but i tried word " or " and there was an compile error
AFAIK, keyword "Or" is not valid in C++ as a boolean operator (or any
other operator for that matter).
You know wrong. "or", "and", "xor", "not" "not_eq", "and_eq",
"compl", "bitor", "bitand", "xor_eq", "or_eq", are reserved as
_alternative_ tokens for "||", "&&" , "^", "!", "!=", "&=",
"~", "|", "&", "^=", "|=", respectively.
If a compiler does not accept those, it's non-compliant.
My fault (newb). Wierd that these were not mentioned in my book, or perhaps
they were & I just missed them.
Jeremy This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics
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