urgent help require

[pacificepoc]

hi everybody
following is the program
Following is the menu to be displayed to the user. On selecting a choice display appropriate result. Number should be accepted from the user.

Menu

1. Prime Factors

2. Leap Year

3. Sum of all digits

4. Number in reverse order


out of this i am not able to the 3 rd part i.e is sum of all digits.
can u tell me how 2 find the sum of all digits that is enterd by the user.

[sicarie]

It seems you have posted this problem before. As I'm sure you read the request that Mary left in the other thread, I was wondering what specific question you had about this program - where did you get stuck? Can you post the code?

[pacificepoc]

It seems you have posted this problem before. As I'm sure you read the request that Mary left in the other thread, I was wondering what specific question you had about this program - where did you get stuck? Can you post the code?

my code
/* Menu Driven Program */

#include<stdio.h>
#include<conio.h>
#include<math.h>
void main()
{

int choice,num,yr,a,n,b,sum,n1,n2,dg;
int temp[];

clrscr();
printf("\n\n1. Prime Factors\n");
printf("2. Leap Year\n");
printf("3. Sum of All digits\n");
printf("4. No. in Reverse Order\n");
printf("5. Exit\n");

printf("\n Enter no. of your Choice : ");
scanf("%d",&choice);

switch(choice)
{
case 1:
printf("Enter the Number :");
scanf("%d",&num);
int i=2;
printf("Prime Factor of the Number is %d : ",num);
while(num!=1)
{
if(num%i==0)
{
printf("%d ",i);
}
else
{
i++;
continue;
}
num=num/i;
}
break;

case 2:
printf("Enter a Year : ");
scanf("%d",&yr);
if(yr%100==0)
{
if(yr%400==0) /* The year is leap year if it is a century year & divisible by 400*/
{
printf("\n Leap Year");
}
else
{
printf("\nNot a Leap Year");

}
}
else
{
if(yr%4==0) /* The year is leap year if it is non-century year & divisible by 4*/
{
printf("\n Leap Year");
}
else
{
printf("Not a leap Year\n");
}
}
break;

case 3:
printf("Enter the Number : ");
scanf("%d",&n);
temp[]=n;
for(i=0;i<=len(temp[]);i++)
{
sum=sum+temp[i];

}
/* while(b<=1)
{
a=n%10;
b=n/10;
sum=0;
sum=sum+a;
n=b;
b--;
}*/
printf("Sum of all digit of the given number is : %d",sum);
break;

case 4:
printf("\nEnter any no.");
scanf("%d",&n1);
/* reverse the number*/
n2=0;
while(n1>0)
{
dg=n1%10;
n2=(n2*10)+dg;
n1=n1/10;
}
printf("The reverse no. is: %d",n2);
break;

case 5:
break;
}
getch();

}




case 3 for calculating the sum of enter no.s but i am not able to do it can u give me the code how to do it i hve to submit it 2mmorrow
Plz

[rajesh6695]

Copy and pase this case 3 and try.....
You have to enter numbers the case 3 will add all the numbers and print at the end of the case ....enter 0 exit entering number.....

C is a structure language you cannot declare the variable in the middile of the code where you had declared the int i = 2; this is not allowed in c


#include<stdio.h>
#include<conio.h>
#include<math.h>
void main()
{

int choice,num,yr,a,n,b,sum,n1,n2,dg;
int i;
int temp[10];

clrscr();
printf("\n\n1. Prime Factors\n");
printf("2. Leap Year\n");
printf("3. Sum of All digits\n");
printf("4. No. in Reverse Order\n");
printf("5. Exit\n");
printf("\n Enter no. of your Choice : ");
scanf("%d",&choice);
switch(choice)
{
case 1:
{
printf("Enter the Number :");
scanf("%d",&num);
i=2;
// int i=2;
printf("Prime Factor of the Number is %d : ",num);
while(num!=1)
{
if(num%i==0)
{
printf("%d ",i);
}
else
{
i++;
continue;
}
num=num/i;
}
}
break;

case 2:
{
printf("Enter a Year : ");
scanf("%d",&yr);
if(yr%100==0)
{
if(yr%400==0) /* The year is leap year if it is a century year & divisible by 400*/
{
printf("\n Leap Year");
}
else
{
printf("\nNot a Leap Year");
}
}
else
{
if(yr%4==0) /* The year is leap year if it is non-century year & divisible by 4*/
{
printf("\n Leap Year");
}
else
{
printf("Not a leap Year\n");
}
}
}
break;

case 3:
{
sum=0;
printf("Enter the Number or 0 to stop entering number :");
do
{
scanf("%d",&n);
sum=sum+n;
}while(n!=0);
printf("Sum of all digit of the given number is : %d",sum);
}
break;

case 4:
{
printf("\nEnter any no.");
scanf("%d",&n1);
/* reverse the number*/
n2=0;
while(n1>0)
{
dg=n1%10;
n2=(n2*10)+dg;
n1=n1/10;
}
printf("The reverse no. is: %d",n2);
}
break;
case 5:
{




}
break;
}
getch();

}

[hirak1984]

first of all practice using functions.this type of approach in writing code is very hard to understand.

use this code and try(this works for a 3 digit number):

printf("enter the number");
scanf("%d",n);
int a=n%10;
int b=(n/10)%10;
int c=n/100;
printf("the sum=%d",(a+b+c));
 

my code
/* Menu Driven Program */

#include<stdio.h>
#include<conio.h>
#include<math.h>
void main()
{

int choice,num,yr,a,n,b,sum,n1,n2,dg;
int temp[];

clrscr();
printf("\n\n1. Prime Factors\n");
printf("2. Leap Year\n");
printf("3. Sum of All digits\n");
printf("4. No. in Reverse Order\n");
printf("5. Exit\n");

printf("\n Enter no. of your Choice : ");
scanf("%d",&choice);

switch(choice)
{
case 1:
printf("Enter the Number :");
scanf("%d",&num);
int i=2;
printf("Prime Factor of the Number is %d : ",num);
while(num!=1)
{
if(num%i==0)
{
printf("%d ",i);
}
else
{
i++;
continue;
}
num=num/i;
}
break;

case 2:
printf("Enter a Year : ");
scanf("%d",&yr);
if(yr%100==0)
{
if(yr%400==0) /* The year is leap year if it is a century year & divisible by 400*/
{
printf("\n Leap Year");
}
else
{
printf("\nNot a Leap Year");

}
}
else
{
if(yr%4==0) /* The year is leap year if it is non-century year & divisible by 4*/
{
printf("\n Leap Year");
}
else
{
printf("Not a leap Year\n");
}
}
break;

case 3:
printf("Enter the Number : ");
scanf("%d",&n);
temp[]=n;
for(i=0;i<=len(temp[]);i++)
{
sum=sum+temp[i];

}
/* while(b<=1)
{
a=n%10;
b=n/10;
sum=0;
sum=sum+a;
n=b;
b--;
}*/
printf("Sum of all digit of the given number is : %d",sum);
break;

case 4:
printf("\nEnter any no.");
scanf("%d",&n1);
/* reverse the number*/
n2=0;
while(n1>0)
{
dg=n1%10;
n2=(n2*10)+dg;
n1=n1/10;
}
printf("The reverse no. is: %d",n2);
break;

case 5:
break;
}
getch();

}




case 3 for calculating the sum of enter no.s but i am not able to do it can u give me the code how to do it i hve to submit it 2mmorrow
Plz

[rajesh6695]

Try this sample code......
Sorry for the above post...

Example
Input 123 output will be 6

#include<stdio.h>
#include<conio.h>
#include<math.h>
void main()
{

int i,j,k,l;
clrscr();
printf("Enter the no :");
scanf("%d",&i);
l=0;
do
{
k=i/10;
j=i%10;
i=k;
l=j+l;
}
while(j);
printf("The value of sum is %d",l);
getch();
return 0;


}