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lvalue with increment operators

Assuming that x is an int, why int* p = &++x is legal and int* p =
&x++ or int* p = &(x++) is illegal.

tia,
Srinivas
Jul 19 '05 #1
1 2586
"srinivas reddy" <sr*************@yahoo.com> wrote...
Assuming that x is an int, why int* p = &++x is legal and int* p =
&x++ or int* p = &(x++) is illegal.


'x++' does not return an lvalue. You cannot take address of
something that is not an lvalue. '++x' returns 'x' after it
has been incremented. And in this case 'x' is an lvalue.

Victor
Jul 19 '05 #2

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