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Obtaining member function/function object's operator() signature

Hi everybody,

in addition to my previous question, first of all this :

template<typename F>
void foo(const F& f)
{
std::cout << boost::function_traits<F>::arity << std::endl;

}

foo(f);

was a great solution for a free functions, so thanks to everybody for
answers :) but, alas, this is not a solution for both member functions
and function objects : boost::function_traits cannot work with any of
these types. any ideas ?..

best regards, Paul Sujkov

Feb 12 '07 #1
1 1642
Thanks for anyone trying to workaround this (if there were any) ;)
issue is solved, no answers are needed anymore...

best regards, Paul Sujkov

Feb 14 '07 #2

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