Hi there,
I'm trying to use an stl map where I have my own defined (templated)
class as a key. I have the class "variableId" below which I want to use
as the key for an stl map. It has two members agent and slot. I've
defined the < operator but I'm slightly confused, here's the complete
class anyhow,
template <typename agentId, typename slotId>
class variableId
{
public:
agentId agent;
slotId slot;
variableId(){}
variableId(agentId aId, slotId sId);
bool operator<(variableId vId);
};
template <typename agentId, typename slotId>
variableId<agentId,slotId>::variableId(agentId aId, slotId sId)
{
agent=aId;
slot=sId;
}
template <typename agentId, typename slotId>
bool variableId<agentId,slotId>::
operator< (variableId vId)
{
return (slot<vId.slot && agent<vId.agent);
}
When I then try and do something like...
map<variableId<int,int>,int> m;
variableId<int,int> varname(1,1);
m[varname] = 1;
I get gcc reporting an error on the line m[varname]=1, something like
/usr/local/include/g++-v3/bits/stl_function.h:141: passing `const
variableId<int, int>' as `this' argument of `bool variableId<agentId,
slotId>::operator<(variableId<agentId, slotId>) [with agentId = int,
slotId = int]' discards qualifiers
I guess I'm either calling incorrecty or I've specified the
class/operator incorrectly.
Any help much appreciated
Thanks
ps. remove ++ from address to reply 3 12676
On Wed, 25 Jun 2003 16:49:02 +0100, Michael H Lees
<mh*@cs.nott.ac.uk++> wrote: Hi there,
I'm trying to use an stl map where I have my own defined (templated) class as a key. I have the class "variableId" below which I want to use as the key for an stl map. It has two members agent and slot. I've defined the < operator but I'm slightly confused, here's the complete class anyhow,
template <typename agentId, typename slotId> class variableId { public: agentId agent; slotId slot; variableId(){} variableId(agentId aId, slotId sId); bool operator<(variableId vId);
Should be:
bool operator<(variableId vId) const;
or
bool operator<(variableId const& vId) const;
};
template <typename agentId, typename slotId> variableId<agentId,slotId>::variableId(agentId aId, slotId sId) { agent=aId; slot=sId; }
template <typename agentId, typename slotId> bool variableId<agentId,slotId>:: operator< (variableId vId) { return (slot<vId.slot && agent<vId.agent); }
template <typename agentId, typename slotId>
bool variableId<agentId,slotId>::
operator< (variableId vId) const
{
return (slot<vId.slot && agent<vId.agent);
}
or
template <typename agentId, typename slotId>
bool variableId<agentId,slotId>::
operator< (variableId const& vId) const
{
return (slot<vId.slot && agent<vId.agent);
}
When I then try and do something like...
map<variableId<int,int>,int> m; variableId<int,int> varname(1,1); m[varname] = 1;
That's fine.
I get gcc reporting an error on the line m[varname]=1, something like
/usr/local/include/g++-v3/bits/stl_function.h:141: passing `const variableId<int, int>' as `this' argument of `bool variableId<agentId, slotId>::operator<(variableId<agentId, slotId>) [with agentId = int, slotId = int]' discards qualifiers
Right, you need a const operator since the key in a map is const. I guess I'm either calling incorrecty or I've specified the class/operator incorrectly.
The latter.
Tom
Michael H Lees wrote: Hi there,
I'm trying to use an stl map where I have my own defined (templated) class as a key. I have the class "variableId" below which I want to use as the key for an stl map. It has two members agent and slot. I've defined the < operator but I'm slightly confused, here's the complete class anyhow,
template <typename agentId, typename slotId> class variableId { public: agentId agent; slotId slot; variableId(){} variableId(agentId aId, slotId sId); bool operator<(variableId vId);
bool operator<(const variableId& vId) const;
};
template <typename agentId, typename slotId> variableId<agentId,slotId>::variableId(agentId aId, slotId sId)
: agent(aId), slot(sId) // prefer initialization lists.
{ agent=aId; slot=sId; }
The above assignments should be replaced by the
initialization list above. template <typename agentId, typename slotId> bool variableId<agentId,slotId>:: operator< (variableId vId)
operator< (const variableId& vId) const
{ return (slot<vId.slot && agent<vId.agent);
// Perhaps some spaces would improve readability:
// (also, return is not a function and doesn't require
// an expression in parenthesis).
return (slot < vId.slot) && (agent < vId.agent);
}
When I then try and do something like...
map<variableId<int,int>,int> m; variableId<int,int> varname(1,1); m[varname] = 1;
I get gcc reporting an error on the line m[varname]=1, something like
/usr/local/include/g++-v3/bits/stl_function.h:141: passing `const variableId<int, int>' as `this' argument of `bool variableId<agentId, slotId>::operator<(variableId<agentId, slotId>) [with agentId = int, slotId = int]' discards qualifiers
I guess I'm either calling incorrecty or I've specified the class/operator incorrectly.
Any help much appreciated
Thanks
ps. remove ++ from address to reply
Add the "const" qualifiers to the "operator <" method above.
The key of a map is constant, but the comparison function wasn't.
--
Thomas Matthews
C++ newsgroup welcome message: http://www.slack.net/~shiva/welcome.txt
C++ Faq: http://www.parashift.com/c++-faq-lite
C Faq: http://www.eskimo.com/~scs/c-faq/top.html
alt.comp.lang.learn.c-c++ faq: http://www.raos.demon.uk/acllc-c++/faq.html
Other sites: http://www.josuttis.com -- C++ STL Library book
Michael H Lees wrote: Replying to my own question.... I know.
I managed to fix the problem by looking at stl::pair as an example.
I redefined the < operator as follows.....
template <class agentId, class slotId> inline bool operator<(const variableId<agentId, slotId>& v1, const variableId<agentId, slotId>& v2) { return (v1.slot<v2.slot && v1.agent<v2.agent); }
I had tried all manner of things but missed the inline option. Should I define all my operators as inline if I'm using the class as a key for a map?
Cheers
_mike_
1. Don't top-post. Replies are either intermixed or appended to
the bottom of a post.
2. A rule of thumb of inlining: Inline simple functions. A get or
a set method is an example. If the overhead of the function
call is greater than the code in the function, then inline the
function.
--
Thomas Matthews
C++ newsgroup welcome message: http://www.slack.net/~shiva/welcome.txt
C++ Faq: http://www.parashift.com/c++-faq-lite
C Faq: http://www.eskimo.com/~scs/c-faq/top.html
alt.comp.lang.learn.c-c++ faq: http://www.raos.demon.uk/acllc-c++/faq.html
Other sites: http://www.josuttis.com -- C++ STL Library book This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics
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