double a = 1e-10;?

[Camellia]

Just a humble question, I tried to assign a real number with exponents
to a variable but obviously I can't do:
double a = 1e-10;
The compiler will in turn complain about the undefined 'e'.

So, how do I suppose to do it?

Thanks in advance.

[Chris Dollin]

Camellia wrote:

Just a humble question, I tried to assign a real number with exponents
to a variable but obviously I can't do:
double a = 1e-10;
The compiler will in turn complain about the undefined 'e'.

For no terribly good reason I can think of, using an exponent
requires that the number contain a decimal point. So

double a = 1.0e-10;

looks like your sentient being. (Yes, I /know/ the 0 after the .
isn't required by the C lexis.)

--
Chris "electric hedgehog" Dollin
Nit-picking is best done among friends.

[Ian Malone]

Camellia wrote:

Just a humble question, I tried to assign a real number with exponents
to a variable but obviously I can't do:
double a = 1e-10;
The compiler will in turn complain about the undefined 'e'.

Have you tried?

#include <stdio.h>

int main(void) {
double a=1e-1;
printf("%f\n",a);
return 0;
}

--
imalone

[Camellia]

On Feb 2, 10:31 pm, Ian Malone <[e-mail]:

Camellia wrote:

Just a humble question, I tried to assign a real number with exponents
to a variable but obviously I can't do:
double a = 1e-10;
The compiler will in turn complain about the undefined 'e'.

Have you tried?

#include <stdio.h>

int main(void) {
double a=1e-1;
printf("%f\n",a);
return 0;

}

--
imalone

I tried:
double a=1e-37;
AGAIN and it worked.

But why the compiler complained about the undefined 'e' last time?

Anyway Thank you guys very much for the help:)

[Chris Dollin]

Chris Dollin wrote:

Complete rubbish, owing to his inability to see the second line
of the floating-constant syntax.

Camellia wrote:

>Just a humble question, I tried to assign a real number with exponents
to a variable but obviously I can't do:
double a = 1e-10;
The compiler will in turn complain about the undefined 'e'.

For no terribly good reason I can think of, using an exponent
requires that the number contain a decimal point.

I'm wrong. Wrong with a big W. Wrong with /3/ big W's: WWWrong,
WWWrong, WWWrong.

Camellia had best show us their non-working code ...

--
Chris "WWWrong hedgehog. NO BICUIT. WroWngW." Dollin
"People are part of the deign. It's dangerou to forget that." /tar Cop/

[Richard Bos]

"Camellia" <br*********@gmail.comwrote:

I tried:
double a=1e-37;
AGAIN and it worked.

But why the compiler complained about the undefined 'e' last time?

Did you perchance have a space between the 1 and the e?

(And if so, that's your cue to change to a monospaced font for code.)

Richard

[Thad Smith]

Richard Bos wrote:

"Camellia" <br*********@gmail.comwrote:

>>I tried:
double a=1e-37;
AGAIN and it worked.

But why the compiler complained about the undefined 'e' last time?

<OT>I encourage Camella to rephrase as "why did ... complain" to get a
complete English sentence. ;-)
</OT>

>
Did you perchance have a space between the 1 and the e?

(And if so, that's your cue to change to a monospaced font for code.)

It's also a reason to paste actual code here, rather than retyping.

--
Thad

[CBFalconer]

Camellia wrote:

>
Just a humble question, I tried to assign a real number with exponents
to a variable but obviously I can't do:
double a = 1e-10;
The compiler will in turn complain about the undefined 'e'.

So, how do I suppose to do it?

Complain to your compiler supplier. Others have given you
work-arounds. It clearly is correct. See the following from N869:

(6.4.4.2) decimal-floating-constant:
fractional-constant exponent-part-opt
floating-suffix-opt
digit-sequence exponent-part
floating-suffix-opt
.... snip ...

(6.4.4.2) fractional-constant:
digit-sequence-opt . digit-sequence
digit-sequence .

(6.4.4.2) exponent-part:
e sign-opt digit-sequence
E sign-opt digit-sequence

(6.4.4.2) sign: one of
+ -

(6.4.4.2) digit-sequence:
digit
digit-sequence digit

--
<http://www.cs.auckland.ac.nz/~pgut001/pubs/vista_cost.txt>

"A man who is right every time is not likely to do very much."
-- Francis Crick, co-discover of DNA
"There is nothing more amazing than stupidity in action."
-- Thomas Matthews

[Keith Thompson]

"Camellia" <br*********@gmail.comwrites:

Just a humble question, I tried to assign a real number with exponents
to a variable but obviously I can't do:
double a = 1e-10;
The compiler will in turn complain about the undefined 'e'.

The declaration

double a = 1e-10;

is perfectly legal. It's possible, but very unlikely, that your
compiler has a bug that causes it to reject this legal code. It's far
more likely that the code you posted is not the code your compiler
complained about, and that you accidentally fixed the error when you
re-typed the code for posting.

For example, if your real code were:

double a = e-10;

the compiler would complain that "e" is undeclared (unless you happen
to have declared something called "e").

If you're having trouble with your code, you need to post the *exact*
code. Don't re-type it; copy-and-paste it.

A minor point: If you want to post about this again, please use a name
other than "a". Since "a" is also an English word, it makes it
difficult to write about it. "x" would be fine.

--
Keith Thompson (The_Other_Keith) ks***@mib.org <http://www.ghoti.net/~kst>
San Diego Supercomputer Center <* <http://users.sdsc.edu/~kst>
We must do something. This is something. Therefore, we must do this.