finding an integer in a string

[jewel87]

Hello, I've got a problem and would appreciate any help.
I have to count the number of integers in a string like this "1.1 some text. 1.2 some text", where it should return 0, as there are no integers, but I still get 2 on the output.
Here is the code:

void IntegerNumber()
{
    int NumberOfIntegers = 0;
    string SubString;
    int flag;
 
    while (!file.eof())
    {
        getline(file, SubString, ' ');
        flag = 0;
        for (int i = 0; i < SubString.length(); i++)
        {
            if (SubString[i] >= '0' && SubString[i]<= '9') flag = 1;
            else flag = 0;
        }
        if (flag == 1) ++NumberOfIntegers;
    }
    cout << "The number of Integers = " << NumberOfIntegers << endl; 
}
 

And I also need a second function, which counts the doubles in the same string, could anyone give me a hint what I need to change in this code for that?
Thanks a lot!

[willakawill]

In your example the 2 integers will be 1 and 1. You need a more sophisticated algorithm to detect the period in the middle. In a normal sentence the period is folowed by a space so you can use this information to detect both an integer and a double.

good luck

[jewel87]

Thanks a lot for your reply!!!
I now got the idea: In the else statement after the flag goes to 0, I've added one line: break; and it is working now!!! ;))