casting _to_ a class/struct

[.rhavin grobert]

Hi there;-)

I have the following struct:

struct foo {
union {
unsigned __int64 ui64;
char[8] c;
};
};

what i now want to make possible is...

foo a;
foo b;
int c;
foo d;
a = "abcdefg";
b = 12;
d = (foo) c;

so i think i need to globally overload the cast operator, isn't it?

i know how to overload the cast-operator to convert from my struct to
$type, but how do i do it the other way 'round?

thanx for your help,

-.rhavin;)

[Andre Kostur]

".rhavin grobert" <cl***@yahoo.dewrote in news:1169841744.091698.6020
@s48g2000cws.googlegroups.com:

Hi there;-)

I have the following struct:

struct foo {
union {
unsigned __int64 ui64;
char[8] c;
};
};

what i now want to make possible is...

foo a;
foo b;
int c;
foo d;
a = "abcdefg";
b = 12;
d = (foo) c;

so i think i need to globally overload the cast operator, isn't it?

Why not assignment operators?

foo & foo::operator=(__int64 newvalue)
{
ui64 = newvalue;
}

foo & foo::operator=(const char * cp)
{
strncpy(c, cp, sizeof(c));
}

i know how to overload the cast-operator to convert from my struct to
$type, but how do i do it the other way 'round?

That would require you to overload operators on int.... can't be done.

[Victor Bazarov]

..rhavin grobert wrote:

[..]
i know how to overload the cast-operator to convert from my struct to
$type, but how do i do it the other way 'round?

I think you're talking about a parameterised constructor here.

V
--
Please remove capital 'A's when replying by e-mail
I do not respond to top-posted replies, please don't ask

[Sylvester Hesp]

"Andre Kostur" <nn******@kostur.netwrote in message
news:Xn*******************************@209.135.99. 21...

".rhavin grobert" <cl***@yahoo.dewrote in news:1169841744.091698.6020

Why not assignment operators?

Because that won't solve the '(foo)c' piece of code ;). Constructors are the
way to go (best in combination with assignment operators, but the latter
won't be needed to make it all work).

- Sylvester