warning: assignment makes integer from pointer without a cast

[gamble1]

Hi,

I am receiving this error when I attempt to assign a value from argv[1] so I can use it as an int.

Here is the code:

int main(int argc, char** argv)
{
FILE* ifp;
int row;

/* Check the command line arguments */
if(argc != 4)
{
fprintf(stderr,"Not enough command line arguments!\n");
fprintf(stderr,"Use %s ROWS COLS OUTPUTFILE\n", argv[0]);
exit(-1);
}

ifp = fopen(argv[3], "r");
if(ifp == NULL)
{
fprintf(stderr,"File %s could not be opened!\n", argv[3]);
exit(-2);
}

row = argv[1];

return 0;
}


My command line arguments are: a.out (number) (number) (filename)

I want to use the numbers entered to create a 2d array, but I can't figure out how to use those numbers entered.

Any help is appreciated. Thank you

[Motoma]

Hi,

I am receiving this error when I attempt to assign a value from argv[1] so I can use it as an int.

Here is the code:

int main(int argc, char** argv)
{
FILE* ifp;
int row;

/* Check the command line arguments */
if(argc != 4)
{
fprintf(stderr,"Not enough command line arguments!\n");
fprintf(stderr,"Use %s ROWS COLS OUTPUTFILE\n", argv[0]);
exit(-1);
}

ifp = fopen(argv[3], "r");
if(ifp == NULL)
{
fprintf(stderr,"File %s could not be opened!\n", argv[3]);
exit(-2);
}

row = argv[1];

return 0;
}


My command line arguments are: a.out (number) (number) (filename)

I want to use the numbers entered to create a 2d array, but I can't figure out how to use those numbers entered.

Any help is appreciated. Thank you

Try this:

   row = atoi(argv[1]);
 

[gamble1]

Try this:

   row = atoi(argv[1]);
 

thank you very much. would you mind explaining what the atoi is. i just want to make sure it's ok with what we have done in class.

thanks again

[Motoma]

thank you very much. would you mind explaining what the atoi is. i just want to make sure it's ok with what we have done in class.

thanks again

atoi() is a function that transforms character string (aka a) to an integer (aka i).