Program Showing its Source Code!!!

[Amit Sharma]

Hi!!! all
i got a program which shows its own source code as output but i m unable to understand what it is plz HELP and EXPLAIN it.

char *f="char*f=% c%s%c;main( ){printf( f,34,f,34, 10);}%c";
main()
{
printf(f,34, f,34,10);
}

Do we have any other way to create the program which shows its source code.

[Motoma]

Hi!!! all
i got a program which shows its own source code as output but i m unable to understand what it is plz HELP and EXPLAIN it.

char *f="char*f=% c%s%c;main( ){printf( f,34,f,34, 10);}%c";
main()
{
printf(f,34, f,34,10);
}

Do we have any other way to create the program which shows its source code.

Okay, well, what is happening is that you are defining a character string which contains a tricky spot of code, as well as the entire body of your program. The program then prints the character string by playing around the the printf() function.

[RedSon]

You might want to consider looking up escape characters in your favorite c/c++ reference material. I think you'll find you have a few spots where you need to escape your punctuation marks.

[khajeddin]

HI:
i had to write this program for my prof afew days ago , and i wrote exactly what you have wrie here for my prof but unfortunatley he said that it isn't correct.please tell me why?!!!????
the other way to print the source code is to send argument to main function and
print the own file of program like this:

int main(char *argc ,int argv[1])
{
FILE *pt;
pt=fopen("argv[0]","rb");
printf("%p",*pt);
}