Wierd output with a command line argument

[Oscarian]

I'm curious to know if anyone can explain why the following code does not
return the second argument exactly, but rather appears to return a random
number (at least it does that on my box).

#include <stdio.h>

int main (int argc, char *argv[]) {
/* Make sure you enter a numerical second argument */
if (argc != 2)
return (0);
printf ("%f\n", atof(argv[1]));
return (0);
}

-Oscarian

[santosh]

Oscarian wrote:

I'm curious to know if anyone can explain why the following code does not
return the second argument exactly, but rather appears to return a random
number (at least it does that on my box).

#include <stdio.h>

int main (int argc, char *argv[]) {
/* Make sure you enter a numerical second argument */
if (argc != 2)
return (0);
printf ("%f\n", atof(argv[1]));
return (0);
}

Include stdlib.h for supplying the prototype for atof, otherwise the
compiler assumes that it returns an int value.

Also consider using strtod which is bit more robust on bad arguments.

[Oscarian]

On Tue, 09 Jan 2007 23:47:33 -0800, santosh wrote:

Include stdlib.h for supplying the prototype for atof, otherwise the
compiler assumes that it returns an int value.

Thanks. That worked.

Cheers-
O