Sum of square integers while loop

[AZRebelCowgirl73]

I am stumped! I am trying to create a program that computes the sum of square integers from 1 to n. I figured out how to find the sum of integers but the square part is absent to me! Can anyone help me!


int main()
{
int n, i, sum;

cout << "Enter a value for n: ";
cin >> n;
sum = 0;
i = 1;
while (i <= n)
{
sum += i;
i++;
}
cout << "The sum of the first " << n
<< " numbers is " << sum << endl;



return 0;
}

[Ganon11]

I am stumped! I am trying to create a program that computes the sum of square integers from 1 to n. I figured out how to find the sum of integers but the square part is absent to me! Can anyone help me!

int main() 
{
    int n, i, sum;
 
    cout << "Enter a value for n: ";
    cin >> n;
    sum = 0;
    i = 1;
    while (i <= n)
    {
        sum += i;
        i++;
    }
    cout << "The sum of the first " << n
    << " numbers is " << sum << endl; 
 
    return 0;
}
 

Right now, you are using "sum += i" which will add the integer i to sum. You say you want to add the square of i instead of i (i.e. i * i). So shouldn't you update that line to

sum += i * i;

[AZRebelCowgirl73]

Right now, you are using "sum += i" which will add the integer i to sum. You say you want to add the square of i instead of i (i.e. i * i). So shouldn't you update that line to

sum += i * i;

Thanks so much! It hit me just as I started to read what you wrote. I so Appreciate your help!!!!!!