Replace words in string

[wizardRahl]

Hello,

I'm looking to write a program that will take a user input (a sentence) and make it less sexist.
For ex., User input is -> He who laughs last, laughs best.
Program output -> She or he who laughs last, laughs best.
or
"A student can get a discount if he shows his ID."

should be replaced by

"A student can get a discount if he or she shows his or her ID."

I'm a little lost on how to scan the string to pick up the pronouns and replace them. Below is what I have so far. I don't expect someone to write this for me, but am looking for a push in the right direction. Any info, source code examples, links, or hints would be most appreciated.

Thanks in advance.
WR

#include <iostream>
#include <string>
using namespace std;
 
 
int main()
{
    string strInput;
 
    cout << "\nPlease enter a gender specific sentence\n";
 
    cout << "or enter `I'm done' to exit the program.\n";
 
         getline(cin, strInput);  //gets the user input
 
          do
              {
            string::size_type loc = strInput.find("he", "him", 0);
 
            if( loc = string::npos )
            string strInput.replace("he", "he or she")||
            string strInput.replace("him", "him or her")
            cout << strInput;
 
            else 
            cout << strInput;
 
            }
            while 
                (strInput != "I'm Done");
 
    return 0;
    }
 
 
 
}

[nickyeng]

find() in string takes one string and one index as following:

size_type find( const string& str, size_type index );

are you sure there is a function for 2 string in find() ?

[wizardRahl]

You mean where I have two instances where I'm trying to look for he and then scanning for him?

No, I'm not sure if it's possible to do it like that.

[nickyeng]

there are many errors in your program.

firstly, find() function for string is as following :

size_type find( const string& str, size_type index );
  size_type find( const char* str, size_type index );
  size_type find( const char* str, size_type index, size_type length );
  size_type find( char ch, size_type index );
 

and your replace() function is also an error argument, it should be one of the following:

 string& replace( size_type index, size_type num, const string& str );
  string& replace( size_type index1, size_type num1, const string& str, size_type index2, size_type num2 );
  string& replace( size_type index, size_type num, const char* str );
  string& replace( size_type index, size_type num1, const char* str, size_type num2 );
  string& replace( size_type index, size_type num1, size_type num2, char ch );
  string& replace( iterator start, iterator end, const string& str );
  string& replace( iterator start, iterator end, const char* str );
  string& replace( iterator start, iterator end, const char* str, size_type num );
  string& replace( iterator start, iterator end, size_type num, char ch );
 

You can't take 2 string argument in replace() and find().

[wizardRahl]

So, in the find part of the code where you you have const string& str, str should be the name of my string (the user input) correct?

Also on the 2nd part with the replace I'd need to use one that iterates because it needs to continue to loop until the user tells it to stop, right? Or does this mean it goes through the string and iterates until all replacements or done?

[wizardRahl]

We also weren't assigned a book for the class, so having to go to outside resources to find examples of everything is quite difficult.

[nickyeng]

We also weren't assigned a book for the class, so having to go to outside resources to find examples of everything is quite difficult.

mine more worst,
i'm self-study.
I only get the material(useless i can tell) from university and study at home alone.
That's why i am here to get help from seniors.

For your questions, i no time to compile and to fix it because i dont have that skills to solve ppl's problem yet.
hehe.
Sorry for that.

be patient to wait, because seniors are helpful.
good luck.

[wizardRahl]

Thanks for the effort; I truly do appreciate any time you take to help.