how to write code...

[dasarath mood]

char id_dir[PATH_MAX] = {0,};
strncpy(id_dir, a->id_file_name, PATH_MAX);
id_dir[PATH_MAX-1] = 0;
strncpy(id_dir, ".d/", PATH_MAX - strnlen(id_dir, PATH_MAX));
struct dirent *id_file = NULL;
do {
errno = 0;
dp = readdir(id_dir)
if (!dp)
break;
/* how add check here to ensure name ends in ".ids"(directory), skip if not. */
f = fopen(id_file, "r");
if(!f)
continue;
err = id_parse_list(a, f, @lino, 1);
fclose(f);
} while (id_file != NULL);

[thefarmer]

your code does'nt have any sense, i think you'd better study first the tutorial of banfa, i think that can help you alot!!!!!!!!!!!!!!!!!

regards,

[DeMan]

That's one way to write code. What does it do?

[dasarath mood]

That's one way to write code. What does it do?

this code is to check the entries in the directory(either current or any specified)...

in this code what i have to do is ..i have add the check to see wheather the name which is listed from this code is available in another directory called example d.ids..if name is available in that(d.ids) directory we have to continue...otherwise we have to skip

[DeMan]

so was there a question, or is this proof you can write code?

[dasarath mood]

so was there a question, or is this proof you can write code?

no..iam asking help to solve this problem

[DeMan]

Not quite sure what the problem is, could you please specify what do you want help with?

[DeMan]

Sorry, missed this line:

/* how add check here to ensure name ends in ".ids"(directory), skip if not. */

not 100% sure what you mean, but I think....

firstly include the string.h library.

there is a function in it strstr(const char* string1,const char *substring) which returns a pointer so you could call
[code]
if(strstr(id_dir, ".ids")!=NULL)
{
//we are good process
}
else
{
//the substring wasn't found
}

NOTE: this is probably not the ideal solution, as it doesn't guarantee the suffix is a suffix, merely that it is in the string (you might want to check the pointer returned is 4 characters before the pointer to the end of the string)