if-else statement

[bitong]

Just cant figure out how to formulate the correct syntax..I can do it in looping statement but my professor said that use only the simple if-else statement. The problem goes like this..Write a program that will determine if the number that you entered is either odd or even number..

I tried writing this code..

#include<stdio.h>
main()
{
int nos;
clrscr();
printf("Enter number:");
scanf("%d",&nos);
if(nos++){
printf("Odd number");
}
else {
printf("Even number");
}
getch();
}

[ssharish]

this is the simple way of finding odd or even

 
if(num % 2 == 0)
    printf("Even\n");
else
  printf("Odd\n");
 
 

there are many different ways of finding odd and even. Depends upon the complexity of your program

main should return value, Have a look at this main

int main()
{
   ---
   ---
   return 0;
}
 

by the way use code tags

ssharish

[bitong]

this is the simple way of finding odd or even

 
if(num % 2 == 0)
    printf("Even\n");
else
  printf("Odd\n");
 
 

there are many different ways of finding odd and even. Depends upon the complexity of your program

main should return value, Have a look at this main

int main()
{
   ---
   ---
   return 0;
}
 

by the way use code tags

ssharish

[quote=bitong]hello...i tried the code that you gave but still it didn't work..

[code]

#include<stdio.h>
int main()
{
int nos;
printf("Enter number:");
scanf("&d",&nos);
if(nos % 2 == 0)
printf("Even number\n");
else
printf("Odd number\n");
getch();
return 0;
}

[DeMan]

In your scanf function you have an & instead of a %

it should be: scanf("%d",&nos);

[bitong]

In your scanf function you have an & instead of a %

it should be: scanf("%d",&nos);

sori...typo error... =)

#include<stdio.h>
int main()
{
int nos;
printf("Enter number:");
scanf("%d",&nos);
if(nos % 2 == 0)
printf("Even number\n");
else
printf("Odd number\n");
getch();
return 0;
}

even though the code goes like that, still any number that I input it brings back the "Even Number" output...even if i entered 3 or 2....

=)

[sivadhas2006]

sori...typo error... =)

#include<stdio.h>
int main()
{
int nos;
printf("Enter number:");
scanf("%d",&nos);
if(nos % 2 == 0)
printf("Even number\n");
else
printf("Odd number\n");
getch();
return 0;
}

even though the code goes like that, still any number that I input it brings back the "Even Number" output...even if i entered 3 or 2....

=)

Hi,

This code is working well.

 
#include<stdio.h>
int main()
{
   int 
      nos = 0;
 
   printf("Enter number:");
   scanf("%d",&nos);
 
   if(nos % 2 == 0)
      printf("Even number\n");
   else
      printf("Odd number\n");
   getch();
   return 0;
}
 
 

Regards,
M.Sivadhas.

[DeMan]

In your print satement, you could add (temporarily of course) a printout of what the number is which might give a clue.

printf("Even Number %d", nos);

Given that it is coming even I would suspect that it is coming through 0, however I must admit the code worked for me.

[bitong]

Hi,

This code is working well.

 
#include<stdio.h>
int main()
{
   int 
      nos = 0;
 
   printf("Enter number:");
   scanf("%d",&nos);
 
   if(nos % 2 == 0)
      printf("Even number\n");
   else
      printf("Odd number\n");
   getch();
   return 0;
}
 
 

Regards,
M.Sivadhas.

Tnx M.Sivadhas...it worked!! =)

[bitong]

Hi,

This code is working well.

 
#include<stdio.h>
int main()
{
   int 
      nos = 0;
 
   printf("Enter number:");
   scanf("%d",&nos);
 
   if(nos % 2 == 0)
      printf("Even number\n");
   else
      printf("Odd number\n");
   getch();
   return 0;
}
 
 

Regards,
M.Sivadhas.

just want to ask whats the function or the purpose of placing % in the "if" statement ---> if(nos % 2 == 0)?

[MariyaGel]

just want to ask whats the function or the purpose of placing % in the "if" statement ---> if(nos % 2 == 0)?

The purpose of placing the % is that ur asking for the remainder after the number is divided by 2. If the remainder is 0 then the number is even. e.g if you do 10 % 6 than that would give you 4.
Hope it helped

[bitong]

The purpose of placing the % is that ur asking for the remainder after the number is divided by 2. If the remainder is 0 then the number is even. e.g if you do 10 % 6 than that would give you 4.
Hope it helped

got it.. =) so it means that putting % in the conditional statement means that you're asking for the remainder of the problem? or its purpose varies depending on how you use it....

[MariyaGel]

got it.. =) so it means that putting % in the conditional statement means that you're asking for the remainder of the problem? or its purpose varies depending on how you use it....

From what I know its the mod operator and so far I only know that you can use it for finding the reminder. Im not sure if it has any other uses. Maybe someone more knowledgeable can answer that question better.
= )

[Banfa]

From what I know its the mod operator and so far I only know that you can use it for finding the reminder. Im not sure if it has any other uses. Maybe someone more knowledgeable can answer that question better.
= )

As an operator that is it's only use.

If I understand bitong correctly they are asking if % can only be used in an if

remembering that the part in the brackets of an if statement is just an expression % can be used anywhere you can validly put an expression.


Another often used method of finding if a number is even is to use the AND bitwise operator &

if (number & 1)
{
// It's odd
}
else
{
// It's even
}

This is not as portable as using the % operator but is usually more efficient as the % operator is one of the less efficient ones.

[thefarmer]

hi,

% in C++ means modulus, it means the remainder of the number you are asking for, so in your program he's asking for the remainder of zero to get an EVEN number so if your number divided by 2 is not zero then the answer should be ODD.

hope it might help??

regards

[bitong]

Hi,

This code is working well.

 
#include<stdio.h>
int main()
{
   int 
      nos = 0;
 
   printf("Enter number:");
   scanf("%d",&nos);
 
   if(nos % 2 == 0)
      printf("Even number\n");
   else
      printf("Odd number\n");
   getch();
   return 0;
}
 
 

Regards,
M.Sivadhas.

hello...just want to ask another question...what is the purpose of putting int in the main() ----> int main()...and putting 0 in variable declaration? ---> int nos=0;

[thefarmer]

hi there,

i hope this might be of help.....

the function "main" like all function must state what kind of value it will return, it is not necessary to use int as always, if not appropriate, you can use " void main () " but mostly depending on your application,

When declaring Variables, C++ provides several different basic data types. The most important ones are:
double: decimal numbers between a smallest, negative one and a largest, positive one
int: a whole number between a smallest, negative one and a largest, positive one
char: a single letter or special symbol, anything that is on your keyboard


ok

regards,

mike

[bitong]

hi there,

i hope this might be of help.....

the function "main" like all function must state what kind of value it will return, it is not necessary to use int as always, if not appropriate, you can use " void main () " but mostly depending on your application,

When declaring Variables, C++ provides several different basic data types. The most important ones are:
double: decimal numbers between a smallest, negative one and a largest, positive one
int: a whole number between a smallest, negative one and a largest, positive one
char: a single letter or special symbol, anything that is on your keyboard


ok

regards,

mike

ok..thnx a lot =)