vector casting

[Chameleon]

class A {}
class B : public A {}

void proceed(vector<A*&in);

void main() {
vector<B*a;
proceed(a); // <-- error here! why?
}

Where is the problem?
I try any static_cast and others but nothing.
There is nothing to produce a problem because elements in any case are
pointers and basically we upcast all elements of vector a. Where is the
problem?

[Ian Collins]

Chameleon wrote:

class A {}
class B : public A {}

void proceed(vector<A*&in);

void main() {
vector<B*a;
proceed(a); // <-- error here! why?

vector<A*and vector<B*are different types.

--
Ian Collins.

[Gianni Mariani]

Chameleon wrote:

class A {}
class B : public A {}

void proceed(vector<A*&in);

void main() {
vector<B*a;
proceed(a); // <-- error here! why?
}

Where is the problem?

vector<A*and vector<B*are different.

I try any static_cast and others but nothing.
There is nothing to produce a problem because elements in any case are
pointers and basically we upcast all elements of vector a. Where is the
problem?

If this was allowed by the compiler, you would inadvertently be allowed
to downcast.

Consider this:

class A {}
class B : public A { double d; }
class C : public A { float f; }

void proceed(vector<A*&in)
{
in[0] = new C;
}

void main() {
vector<B*a;
proceed(a);

a[0].d=3; // oops !
}

vector<A*and vector<B*are as different as class X {}; and class Y
{}; They're not related.

[Mark P]

Chameleon wrote:

class A {}
class B : public A {}

void proceed(vector<A*&in);

void main() {
vector<B*a;
proceed(a); // <-- error here! why?
}

Where is the problem?
I try any static_cast and others but nothing.
There is nothing to produce a problem because elements in any case are
pointers and basically we upcast all elements of vector a. Where is the
problem?

Just because B derives from A does not imply that vector<B*derives
from vector<A*>-- indeed it does not. Among other possibilities, you
can declare the vector as vector<A*>, copy the contents of vector<B*>
to a vector<A*>, or overload the function to accept a vector<B*>.

[Amadeus W.M.]

On Sat, 25 Nov 2006 04:12:30 +0200, Chameleon wrote:

class A {}
class B : public A {}

void proceed(vector<A*&in);

void main() {
vector<B*a;
proceed(a); // <-- error here! why?
}

Where is the problem?
I try any static_cast and others but nothing.
There is nothing to produce a problem because elements in any case are
pointers and basically we upcast all elements of vector a. Where is the
problem?

Because you're declaring proceed(vector<A*&) but you call it on
vector<B*>, I'm guessing you want proceed() to work on both vector<A*>
and vector<B*(which are unrelated types), or on
vector<other_descendants_of_A>. If so, make proceed() a template:

template <class X>
void proceed(vector<X*& a);

[Jim Langston]

"Chameleon" <ch******@hotmail.comwrote in message
news:ek**********@volcano1.grnet.gr...

class A {}
class B : public A {}

void proceed(vector<A*&in);

void main() {
vector<B*a;
proceed(a); // <-- error here! why?
}

Where is the problem?
I try any static_cast and others but nothing.
There is nothing to produce a problem because elements in any case are
pointers and basically we upcast all elements of vector a. Where is the
problem?

an A pointer can contain a B pointer with polymorphism, but a B pointer
can't contain an A pointer.

Maybe you are thinking of this.

class A{};
class B: public A {};

void proceed( std::vector<A*>& in );

void main()
{
std::vector<A*a;
// even though this is a vector of A*, you can still push B's onto it.
a.push_back( new B() );

proceed( a );
}

[Salt_Peter]

Chameleon wrote:

class A {}
class B : public A {}

void proceed(vector<A*&in);

void main() {
vector<B*a;
proceed(a); // <-- error here! why?
}

Where is the problem?
I try any static_cast and others but nothing.
There is nothing to produce a problem because elements in any case are
pointers and basically we upcast all elements of vector a. Where is the
problem?

If you had a std::vector<A*with B* elements, then you'ld proceed(a)
with no problems.