problem with fibonacci series

[srinpraveen]

I know to write a program to print the fibonacci series. But the problem is my teacher has asked us to write a program to print the natural numbers that are not involved in the fibonacci series.
For example if the user gives 7 terms of the series to be displayed,
then the display of the fibonacci series is 0, 1,1, 2, 3, 5, 8.
But the natural numbers not involved are 4, 6 and 7. That's what my teacher wants.
But I am struggling to write a program to perform this particular operation. Can anyone help?

[palani12kumar]

Try to generate the fibonacci series upto the range of the given number and store it in an array. Then using the for loop find the numbers that are not involved in the fibonacci series and print

[srinpraveen]

Ya I know that logic but when I tried to put it down in coding, I feel that somewhere I have gone wrong in the coding. Why don't you send me the coding so that I can see if mine tallies with yours or otherwise where I have gone wrong. Later I will post my coding so that you can spot out where I am having problem because right now I am preparing for exam. In the mean time, I would appreciate if you could send in your coding for this program.

[Manjiri]

Try out with this ... U will get the ans
#include<stdio.h>
int main()
{
int f1,f2,f3,k,n;
printf("Enter the last element\n");
scanf("%d",&n);
f1=1;
f2=2;
f3=f1+f2;
while(f3<n)
{
f1=f2;
f2=f3;
f3=f1+f2;
k=f2;

while(k<f3-1 && k<=n-1)
{
k++;
printf("%4d",k);
}
}
return 0;
}

[Manjiri]

Try out with this ... U will get the ans...

#include<stdio.h>
int main()
{
int f1,f2,f3,k,n;
printf("Enter the last element\n");
scanf("%d",&n);
f1=1;
f2=2;
f3=f1+f2;
while(f3<n)
{
f1=f2;
f2=f3;
f3=f1+f2;
k=f2;

while(k<f3-1 && k<=n-1)
{
k++;
printf("%4d",k);
}
}
return 0;
}

[srinpraveen]

thanks I will try it out soon

[srinpraveen]

Wow, it is working...thanks a lot and I really appreciate that help

[Manjiri]

Wow, it is working...thanks a lot and I really appreciate that help

It's ok....
And thanks for the complements...

[Creative]

You may try this program to get natural numbers like 4,7 in a fibonacci series:
#include<iostream.h>
#include<conio.h>
int main()
{
clrscr();
unsigned long a,b,c,n;
a=2;
b=1;
cout<<"How many numbers(>5)?"<<"\n";
cin>>n;
cout<<"Fibonacci series"<<"\n";
cout<<a<<b;
for(int i=2,i<n;i++)
{
c=a+b;
cout<<c;
a=b;
b=c;
}
getch();
return 0;
}

The Output will be as:
2134711

By giving b=2,You will get the output as:
22461016
In this way you can get the natural numbers like 4,6,7 in a fibonacci series.

We can't get a series with 4,6,7 coming together,since the sum of 4 and 6 will certainly give as 10 and not as 7.
I hope that this helped you.