By using this site, you agree to our updated Privacy Policy and our Terms of Use. Manage your Cookies Settings.
454,605 Members | 1,391 Online
Bytes IT Community
+ Ask a Question
Need help? Post your question and get tips & solutions from a community of 454,605 IT Pros & Developers. It's quick & easy.

Question : 3d array with pointer to pointer.

P: n/a
I was trying to define 3d array with pointer to pointer. I wrote like
following.

int ***d;
nx = 3;
ny = 5;
nz = 4;

d = (int ***)malloc((int) nx*sizeof(int **));
*d = (int **)malloc((int) nx*ny*sizeof(int*));
**d = (int *)malloc((int) nx*ny*nz*sizeof(int));
for(i = 1; i < nx ; i++) d[i] = d[i-1] + ny;
for(i = 0; i < nx ; i++)
for(j = 1; j < ny ; j++) d[i][j] = d[i][j-1] + nz;
for(i=0 ; i < nx; i ++)
for(j = 0; j < ny; j++)
for(k = 0 ; k < nz; k++)
d[i][j][k] = 100*(i+1) + 10*(j+1) + k;
it compiled ok. but when I ran it, it shows error message like
"segementation fault.."

What did I do wrong ? can someone help me ?

thank you.

Nov 12 '06 #1
Share this Question
Share on Google+
4 Replies


P: n/a
Joonshik Kim said:
I was trying to define 3d array with pointer to pointer. I wrote like
following.

int ***d;
nx = 3;
ny = 5;
nz = 4;
d = malloc(nx * sizeof *d);
if(d == NULL) { HANDLE_THE_ERROR; }

for(i = 0; i < nx; i++)
{
d[i] = malloc(ny * sizeof *d[i]);
if(d[i] == NULL) { CLEAN_UP; HANDLE_THE_ERROR; }

for(j = 0; j < ny; j++)
{
d[i][j] = malloc(nz * sizeof *d[i][j]);
if(d[i][j] == NULL) { CLEAN_UP; HANDLE_THE_ERROR; }
for(k = 0; k < nz; k++)
{
d[i][j][k] = 42;
--
Richard Heathfield
"Usenet is a strange place" - dmr 29/7/1999
http://www.cpax.org.uk
email: normal service will be restored as soon as possible. Please do not
adjust your email clients.
Nov 12 '06 #2

P: n/a
Oh..Thank you..
It works nice..

"Richard Heathfield" <in*****@invalid.invalidwrote in message
news:pq******************************@bt.com...
Joonshik Kim said:
I was trying to define 3d array with pointer to pointer. I wrote like
following.

int ***d;
nx = 3;
ny = 5;
nz = 4;

d = malloc(nx * sizeof *d);
if(d == NULL) { HANDLE_THE_ERROR; }

for(i = 0; i < nx; i++)
{
d[i] = malloc(ny * sizeof *d[i]);
if(d[i] == NULL) { CLEAN_UP; HANDLE_THE_ERROR; }

for(j = 0; j < ny; j++)
{
d[i][j] = malloc(nz * sizeof *d[i][j]);
if(d[i][j] == NULL) { CLEAN_UP; HANDLE_THE_ERROR; }
for(k = 0; k < nz; k++)
{
d[i][j][k] = 42;
--
Richard Heathfield
"Usenet is a strange place" - dmr 29/7/1999
http://www.cpax.org.uk
email: normal service will be restored as soon as possible. Please do not
adjust your email clients.

Nov 12 '06 #3

P: n/a
Richard Heathfield wrote:
[snip]
--
Richard Heathfield
"Usenet is a strange place" - dmr 29/7/1999
http://www.cpax.org.uk
email: normal service will be restored as soon as possible. Please do not
adjust your email clients.
Hi Richard, it's Sarah Thompson here. I've been trying to contact you
urgently, but haven't succeeded through usual channels, so many
apologies for posting here but I am not aware of any alternative.

You need to contact your brother Robert urgently in connection with a
family matter. Feel free to email me directly and I'll fill you in on
the details.

Best regards,
Sarah (thompson a t email dt arc dt nasa d t gov)

Nov 15 '06 #4

P: n/a

Joonshik Kim wrote:
I was trying to define 3d array with pointer to pointer. I wrote like
following.

int ***d;
nx = 3;
ny = 5;
nz = 4;

d = (int ***)malloc((int) nx*sizeof(int **));
You store one address into d.
*d = (int **)malloc((int) nx*ny*sizeof(int*));
You store one address at *d.
**d = (int *)malloc((int) nx*ny*nz*sizeof(int));
You store one address at **d.
for(i = 1; i < nx ; i++) d[i] = d[i-1] + ny;
for(i = 0; i < nx ; i++)
for(j = 1; j < ny ; j++) d[i][j] = d[i][j-1] + nz;
You now try to access 60 addresses. What is wrong with this picture?

Nov 15 '06 #5

This discussion thread is closed

Replies have been disabled for this discussion.