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void umg()

P: 1
I have a question, what does void umg mean in this C++ program code?

void umg(x){
char a[]=x;
for(i=n-1;i>=0; i--){
cout <<zeile [i];
Nov 11 '06 #1
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Expert Mod 5K+
P: 8,916
it is defining the function umg that doesn't return anything. There should be a type before the x and I wouldn't expect this to compile
Nov 11 '06 #2

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