pls help me banfa

[anarghya]

an integer is divisible by 11 if the sum of the digits in odd position
equates to the sum of the digits in even position of the integer.Write
a program in C to find whether a given integer is divisible by 11
following the above rule.

[sicarie]

an integer is divisible by 11 if the sum of the digits in odd position
equates to the sum of the digits in even position of the integer.Write
a program in C to find whether a given integer is divisible by 11
following the above rule.

Where are you having trouble?

[anarghya]

my trouble is i donot construct this program?

[sivadhas2006]

Hi,

This may be help your need.
This is one way to implement your logic.

 
#include <iostream.h>
#include <string.h>
#include <stdlib.h>
 
int main(int argc, char* argv[])
{
   int
      nInput = 0,
      nIndex = 0,
      nInputLength = 0,
      nOddDigitsTotal = 0,
      nEvenDigitsTotal = 0;      
   char
      szTemp[2],
      szInput[10];
 
   // Get the input.
   cout << "Enter the number : ";
   cin >> nInput;
 
   // Convert to string.
   itoa(nInput, szInput, 10);
 
   // Get the length of the string.
   nInputLength = strlen(szInput);
   szTemp[1] = 0;
   for(nIndex = 0; nIndex < nInputLength; nIndex++)
   {
      szTemp[0] = szInput[nIndex];
      if(nIndex % 2 == 1)
      {         
         nOddDigitsTotal = nOddDigitsTotal + atoi(szTemp);
      }
      else
      {
         nEvenDigitsTotal = nEvenDigitsTotal + atoi(szTemp);
      }      
   }
 
   // Check whether the odd digits total is e
   if(nOddDigitsTotal == nEvenDigitsTotal)
   {
      cout << "The " << nInput << " is divisible by 11.";
   }
   else
   {
      cout << "The " << nInput << " is not divisible by 11.";
   }   
   return 0;
}
 
 
 

Regards,
M.Sivadhas.