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i need to develop a code that finds a prime right number between 2 and
100000. and print one line of text that indicates if the int. is right
prime. i am in beginning programing so complex is complicated. we are
on a functions chapter. i am usung the square root to find the prime.
so far i have accomplished this but i cant fgure how to divide this by
ten so i can find the right prime. i am using c.
#include <stdio.h>
#include <math.h>
int slowPrime(int); //function prototype
int main()
{
int x; // loop counter
int count = 0; // total numbers of prime found
long prime;
printf_s("The prime numbers from 1 to 10000 are:\n" );
for ( x = 2; x <= 2147483647 ; x++ )
{
if ( Prime( x ) )
{
++count; // count and print prime
//printf_s("%10d", x );
if ( count % 10 == 0 ) // new line after 10 values diplayed
printf_s( "\n" );
} // end for
} // end if
printf_s("%d prime numbers were found\n", count);
return 0; // indicate successful termination
} // end main
int isRightPrime( int n ) // slow prime returns 1 if n is prime
{
int i; // loop counter
for ( i = 2; i <= (int)sqrt (n); i++ )
{
if ( n % i == 0 )
return 0;
} // end for
return 1;
} // end function prime
i know this can not be as complicated as i have made it.  
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On Tue, 7 Nov 2006 jo********@gmail.com wrote:
>
i need to develop a code that finds a prime right number between 2 and
100000. and print one line of text that indicates if the int. is right
prime. i am in beginning programing so complex is complicated. we are
on a functions chapter. i am usung the square root to find the prime.
so far i have accomplished this but i cant fgure how to divide this by
ten so i can find the right prime. i am using c.
Is "right prime" different from "prime"?
#include <stdio.h>
#include <math.h>
int slowPrime(int); //function prototype
int main()
{
int x; // loop counter
Your indentation got messed up by your newsreader; I've restored proper
indentation below.
int count = 0; // total numbers of prime found
long prime;
printf_s("The prime numbers from 1 to 10000 are:\n" );
'printf_s' should be 'printf', of course.
for ( x = 2; x <= 2147483647 ; x++ )
When will this loop terminate if INT_MAX (the maximum possible value of
an 'int') is 32767? What if INT_MAX is 2147483647? Remember, all ints
are by definition at most INT_MAX  there are no ints greater than
INT_MAX.
Also, you might consider how many even primes there are, and then
modify your program accordingly.
{
if (Prime(x)) {
I haven't seen a prototype for 'Prime' yet. You should put declarations
for all your functions (except, usually, 'main') at the top of your
program, or at least somewhere prior to their first use.
++count; // count and print prime
//printf_s("%10d", x );
if (count % 10 == 0) // new line after 10 values diplayed
printf_s( "\n" );
} // end for
} // end if
printf_s("%d prime numbers were found\n", count);
return 0; // indicate successful termination
} // end main
int isRightPrime( int n ) // slow prime returns 1 if n is prime
{
int i; // loop counter
for (i=2; i <= (int)sqrt(n); i++) {
As before, consider that there is only one even prime. Look up the
"Sieve of Eratosthenes", if you haven't yet.
Also notice that "i <= (int)sqrt(n)" is basically testing the same
thing as "i*i <= n". Which of those two expressions do you think would
execute faster on a realworld computer?
if (n % i == 0)
return 0;
} // end for
return 1;
} // end function prime
Where's the definition of 'Prime'? I also notice that the function
'isRightPrime' was never used.
i know this can not be as complicated as i have made it.
Modulo all those elementary errors and bugs, you've got the basic
naive algorithm for prime testing. There's nothing wrong with using it
for tiny numbers (say, numbers less than 2^32). For bigger numbers,
there are faster algorithms.
Arthur  
P: n/a
 jo********@gmail.com wrote:
i need to develop a code that finds a prime right number between 2 and
100000. and print one line of text that indicates if the int. is right
prime. i am in beginning programing so complex is complicated. we are
on a functions chapter. i am usung the square root to find the prime.
so far i have accomplished this but i cant fgure how to divide this by
ten so i can find the right prime. i am using c.
#include <stdio.h>
#include <math.h>
int slowPrime(int); //function prototype
int main()
{
int x; // loop counter
int count = 0; // total numbers of prime found
long prime;
printf_s("The prime numbers from 1 to 10000 are:\n" );
for ( x = 2; x <= 2147483647 ; x++ )
{
if ( Prime( x ) )
{
++count; // count and print prime
//printf_s("%10d", x );
if ( count % 10 == 0 ) // new line after 10 values diplayed
printf_s( "\n" );
} // end for
} // end if
printf_s("%d prime numbers were found\n", count);
return 0; // indicate successful termination
} // end main
int isRightPrime( int n ) // slow prime returns 1 if n is prime
{
int i; // loop counter
for ( i = 2; i <= (int)sqrt (n); i++ )
{
if ( n % i == 0 )
return 0;
} // end for
return 1;
} // end function prime
i know this can not be as complicated as i have made it.
True, and I'm still a little unclear as to your question.
But I can offer a couple of things that might be usefull.
1:
for ( x = 2; x <= 2147483647 ; x++ )
is wasting cycles checking even numbers for primes.
try this
for ( x = 3; x <= 2147483647 ; x+=2 )
you already know 2 is prime so do your other
stuff on it before the for loop begins
2:
Is this the correct definition of a right prime?
"if N is prime and all numbers obtained by successively removing the
rightmost digits of N are prime then its a "right prime"."
based on that here's a fn that should do it
(its untested, off the top of my head, so it might be buggy)
Eric
const int true = 1;
const int false = 0;
int IsRightPrime(unsigned long long int PrimeNumber)
{
char Prime[33]; // set this to max digits in PrimeNumber + 1
int i, lastchar;
unsigned long long int testNum;
sprintf(Prime, "%lld", PrimeNumber)
lastchar = strlen(Prime)1;
for(i=lastchar; i>0; i) {
Prime[i] = 0; // drop last digit
testNum = strtoull(Prime[i], NULL, 10);
if(!Prime(testNum)) return false
}
return true;
}
//  
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Eric wrote: jo********@gmail.com wrote:
>i need to develop a code that finds a prime right number between 2 and 100000. and print one line of text that indicates if the int. is right prime. i am in beginning programing so complex is complicated. we are on a functions chapter. i am usung the square root to find the prime. so far i have accomplished this but i cant fgure how to divide this by ten so i can find the right prime. i am using c. #include <stdio.h> #include <math.h>
int slowPrime(int); //function prototype
int main() { int x; // loop counter int count = 0; // total numbers of prime found long prime;
printf_s("The prime numbers from 1 to 10000 are:\n" );
for ( x = 2; x <= 2147483647 ; x++ ) { if ( Prime( x ) ) { ++count; // count and print prime //printf_s("%10d", x );
if ( count % 10 == 0 ) // new line after 10 values diplayed printf_s( "\n" ); } // end for } // end if
printf_s("%d prime numbers were found\n", count);
return 0; // indicate successful termination } // end main
int isRightPrime( int n ) // slow prime returns 1 if n is prime { int i; // loop counter
for ( i = 2; i <= (int)sqrt (n); i++ ) { if ( n % i == 0 ) return 0;
} // end for
return 1;
} // end function prime i know this can not be as complicated as i have made it.
True, and I'm still a little unclear as to your question.
But I can offer a couple of things that might be usefull.
1:
for ( x = 2; x <= 2147483647 ; x++ )
is wasting cycles checking even numbers for primes.
try this
for ( x = 3; x <= 2147483647 ; x+=2 )
you already know 2 is prime so do your other
stuff on it before the for loop begins
2:
Is this the correct definition of a right prime?
"if N is prime and all numbers obtained by successively removing the
rightmost digits of N are prime then its a "right prime"."
based on that here's a fn that should do it
(its untested, off the top of my head, so it might be buggy)
Eric
const int true = 1;
const int false = 0;
int IsRightPrime(unsigned long long int PrimeNumber)
{
char Prime[33]; // set this to max digits in PrimeNumber + 1
int i, lastchar;
unsigned long long int testNum;
sprintf(Prime, "%lld", PrimeNumber)
lastchar = strlen(Prime)1;
for(i=lastchar; i>0; i) {
Prime[i] = 0; // drop last digit
testNum = strtoull(Prime[i], NULL, 10);
if(!Prime(testNum)) return false
}
return true;
}
//
ahem: (after staring at it a bit after posting...)
char Prime[33]; // set this to max digits in PrimeNumber + 1
int i, lastchar;
unsigned long long int testNum;
sprintf(Prime, "%lld", PrimeNumber);
lastchar = strlen(Prime)1;
for(i=lastchar; i>0; i) {
Prime[i] = 0; // drop last digit
testNum = strtoull(Prime, NULL, 10);
if(!IsPrime(testNum)) return false;
}
return true;
}  
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In article <11**********************@f16g2000cwb.googlegroups .com>,
<jo********@gmail.comwrote:
>#include <stdio.h> #include <math.h>
>int slowPrime(int); //function prototype
Your use of // comments indicate that you are using C99.
>int main()
If I recall correctly, that is not a valid declaration of main in C99.
[But I could be misremembering.] Try
int main(void)
Not that it will likely make any noticable difference, but it will
at least fix the language level incompatability.
>for ( x = 2; x <= 2147483647 ; x++ ) { if ( Prime( x ) ) { ++count; // count and print prime //printf_s("%10d", x );
You appear to have commented out printing of the primes. And you
do not appear to be leaving a space between the primes being printed.

Is there any thing whereof it may be said, See, this is new? It hath
been already of old time, which was before us.  Ecclesiastes  
P: n/a
 ro******@ibd.nrccnrc.gc.ca (Walter Roberson) writes:
In article <11**********************@f16g2000cwb.googlegroups .com>,
<jo********@gmail.comwrote:
>>#include <stdio.h> #include <math.h>
>>int slowPrime(int); //function prototype
Your use of // comments indicate that you are using C99.
Or a compiler that supports // comments as an extension (many of them
do). But it's a bad idea to use // comments in code posted to Usenet;
line wrapping can easily introduce syntax errors.
>>int main()
If I recall correctly, that is not a valid declaration of main in C99.
[But I could be misremembering.] Try
int main(void)
Not that it will likely make any noticable difference, but it will
at least fix the language level incompatability.
I believe "int main()" is valid, but "int main(void)" is preferred.
("int main()" declares main as a function taking an unspecified number
and type(s) of arguments, but if it's part of a definition it's ok.
But "int main(void)" is more explicit, and there's no good reason not
to specify the "void" explicitly.)
>>for ( x = 2; x <= 2147483647 ; x++ ) { if ( Prime( x ) ) { ++count; // count and print prime //printf_s("%10d", x );
You appear to have commented out printing of the primes. And you
do not appear to be leaving a space between the primes being printed.
Using the "%10d" format means there will be spaces between the primes
as long as they're less than 10 digits  assuming that the
nonstandard (or at least otherstandard) "printf_s" behaves like
"printf".

Keith Thompson (The_Other_Keith) ks***@mib.org <http://www.ghoti.net/~kst>
San Diego Supercomputer Center <* <http://users.sdsc.edu/~kst>
We must do something. This is something. Therefore, we must do this.  
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Keith Thompson said:
Walter Roberson writes:
><jo********@gmail.comwrote:
<snip>
>>>int main()
If I recall correctly, that is not a valid declaration of main in C99. [But I could be misremembering.]
<snip>
I believe "int main()" is valid, but "int main(void)" is preferred.
There is no need for us to recall or believe. We can simply consult the
Standard, and then we'll know for sure. See 6.7.5.3, which says in part:
"An empty list in a function declarator that is part of a definition of that
function specifies that the function has no parameters."
Therefore, in a function definition, int main() and int main(void) are
equivalent, and therefore a function definition beginning with int main()
is welldefined, by the equivalence rule of 5.1.2.2.1(1).

Richard Heathfield
"Usenet is a strange place"  dmr 29/7/1999 http://www.cpax.org.uk
email: normal service will be restored as soon as possible. Please do not
adjust your email clients.  
P: n/a
 jo********@gmail.com wrote:
i need to develop a code that finds a prime right number between 2 and
100000. and print one line of text that indicates if the int. is right
prime.
what's a "right prime"?
i am in beginning programing so complex is complicated. we are
on a functions chapter. i am usung the square root to find the prime.
??
so far i have accomplished this but i cant fgure how to divide this by
ten so i can find the right prime. i am using c.
#include <stdio.h>
#include <math.h>
int slowPrime(int); //function prototype
useless comment, you never declare this function
int main()
{
int x; // loop counter
int count = 0; // total numbers of prime found
long prime;
you never use this
printf_s("The prime numbers from 1 to 10000 are:\n" );
what is print_s? You said you were going to print the primes below
100000...
for ( x = 2; x <= 2147483647 ; x++ )
2147483647 != 10000
2147483647 != 100000
{
if ( Prime( x ) )
no prototype in scope. No declaration.
{
++count; // count and print prime
//printf_s("%10d", x );
if ( count % 10 == 0 ) // new line after 10 values diplayed
printf_s( "\n" );
} // end for
} // end if
if you laid your program out correctly you would (a) notice that these
comments are incorrect (b) not need them
printf_s("%d prime numbers were found\n", count);
return 0; // indicate successful termination
} // end main
int isRightPrime( int n ) // slow prime returns 1 if n is prime
this is never called
{
int i; // loop counter
for ( i = 2; i <= (int)sqrt (n); i++ )
{
if ( n % i == 0 )
return 0;
} // end for
return 1;
} // end function prime
i know this can not be as complicated as i have made it.
Now post something that compiles.

Nick Keighley
"There are two ways of constructing a software design: One way is to
make it so simple that there are obviously no deficiencies, and the
other way is to make it so complicated that there are no obvious
deficiencies. The first method is far more difficult."
 C.A.R. Hoare  
P: n/a

Nick Keighley said: jo********@gmail.com wrote:
<snip>
>> int slowPrime(int); //function prototype
useless comment, you never declare this function
But he just did! That *is* a declaration!
<snip>

Richard Heathfield
"Usenet is a strange place"  dmr 29/7/1999 http://www.cpax.org.uk
email: normal service will be restored as soon as possible. Please do not
adjust your email clients.  
P: n/a

Nick Keighley wrote:
jo********@gmail.com wrote:
>i need to develop a code that finds a prime right number between 2 and 100000. and print one line of text that indicates if the int. is right prime.
what's a "right prime"?
By analogy with a right whale, it is slow, fat and blubbery, easy
to catch, and an endangered species.

Chuck F (cbfalconer at maineline dot net)
Available for consulting/temporary embedded and systems.
<http://cbfalconer.home.att.net>  
P: n/a

CBFalconer wrote:
Nick Keighley wrote:
jo********@gmail.com wrote:
i need to develop a code that finds a prime right number between
2 and 100000. and print one line of text that indicates if the
int. is right prime.
what's a "right prime"?
By analogy with a right whale, it is slow, fat and blubbery, easy
to catch, and an endangered species.
And floats after being harpooned.
Brian  
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Richard Heathfield wrote:
Nick Keighley said: jo********@gmail.com wrote:
<snip>
>
int slowPrime(int); //function prototype
useless comment, you never declare this function
But he just did! That *is* a declaration!
<snip>
I swopped definition and declaration (again). :(

Nick Keighley  
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#include <stdio.h>
/* This program implements a blindingly fast O(n^n) algorithm to
find right prime numbers, using an elegant recursive method.
It does not use the square root function, which is very slow. */
int _(int n, int m, int d)
{
int r = m != n;
for(int i=0; d && (i<n); i++)
r *= _(n,(m<=n)?i*m:0,d1)!_(i,1,i);
return r;
}
/*
Print right primes up to the requested value
*/
int main(int argc, char* argv[])
{
for(int n = 2; n < 100000; n++)
printf("%d is%s right prime\n",n, _(n,1,n)?"" : " not");
return 0;
} jo********@gmail.com wrote:
i need to develop a code that finds a prime right number between 2 and
100000. and print one line of text that indicates if the int. is right
prime. i am in beginning programing so complex is complicated. we are
on a functions chapter. i am usung the square root to find the prime.
so far i have accomplished this but i cant fgure how to divide this by
ten so i can find the right prime. i am using c.
i know this can not be as complicated as i have made it.
 
P: n/a

"Don" <do*******@gmail.comwrites:
jo********@gmail.com wrote:
>i need to develop a code that finds a prime right number between 2 and 100000. and print one line of text that indicates if the int. is right prime. i am in beginning programing so complex is complicated. we are on a functions chapter. i am usung the square root to find the prime. so far i have accomplished this but i cant fgure how to divide this by ten so i can find the right prime. i am using c.
i know this can not be as complicated as i have made it.
#include <stdio.h>
/* This program implements a blindingly fast O(n^n) algorithm to
find right prime numbers, using an elegant recursive method.
It does not use the square root function, which is very slow. */
[code snipped]
Please don't toppost. See the following:
http://www.caliburn.nl/topposting.html
http://www.cpax.org.uk/prg/writings/topposting.php
I still have no idea what a "right prime" number is, as opposed to a
prime number. Unless you happen to be familiar with the term, there's
not much point in replying until and unless the OP explains what he
really means.

Keith Thompson (The_Other_Keith) ks***@mib.org <http://www.ghoti.net/~kst>
San Diego Supercomputer Center <* <http://users.sdsc.edu/~kst>
We must do something. This is something. Therefore, we must do this.  
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"Ksitami" <ks*****@gmail.comwrites:
http://mathworld.wolfram.com/TruncatablePrime.html
Please provide context when you post a followup. The context was my
comment:
 I still have no idea what a "right prime" number is, as opposed to a
 prime number. Unless you happen to be familiar with the term, there's
 not much point in replying until and unless the OP explains what he
 really means.
I see no evidence that what the web page describes is what the
original poster had in mind. Since the OP was asked repeatedly what
he meant by "right prime" and never bothered to answer, I suggest that
we not waste any more time trying to answer his original question.
(In fact, the code in the original post appears to deal only with
ordinary primes.)
I suggest the following guideline for this newsgroup. (I intend to
follow it myself; others will do as they like).
If you post a question, someone asks you for a clarification, and you
don't reply, then it's safe to assume that you weren't really
interested in getting an answer, and we needn't waste any further time
until and unless you explain what you meant. (That's a general "you",
not referring to any specific purpose.)
I see a lot of discussions here in which people speculate at great
length about what the OP really meant. If you enjoy such speculation,
that's fine, but I suggest that we're under no obligation to figure
out the meaning of an unclear question if the OP is unwilling to
explain it to us.

Keith Thompson (The_Other_Keith) ks***@mib.org <http://www.ghoti.net/~kst>
San Diego Supercomputer Center <* <http://users.sdsc.edu/~kst>
We must do something. This is something. Therefore, we must do this.  
P: n/a

function isprime(p:dword):boolean;
var i,s:dword;
begin
result:=false;
if p<2 then exit;
if p<4 then begin
result:=true;
exit
end;
if (p mod 2=0) or (p mod 3=0) then
exit;
i:=5; s:=round(sqrt(p));
while i<=s do begin
if p mod i=0 then exit;
i+=2;
if p mod i=0 then exit;
i+=4
end;
result:=true
end;
const
nsp=5;
sp:array[1..nsp] of dword=(1,3,5,7,9);
procedure x(r:dword);
var i:dword;
begin
if isprime(r) then begin
writeln(r:9);
for i:=1 to nsp do
x(r*10 + sp[i]);
end;
end;
begin
l:=0; lt:=0;
x(2); writeln(#10);
x(3); writeln(#10);
x(5); writeln(#10);
x(7); writeln(#10);
writeln(lt);
end.  
P: n/a

Keith Thompson wrote:
(In fact, the code in the original post appears to deal only with
ordinary primes.)
Well, if you find all the primes you know you have both the right and
the wrong ones :)  
P: n/a

"Ksitami" <ks*****@gmail.comwrites:
function isprime(p:dword):boolean;
var i,s:dword;
[snip]
You posted a program in some language that closely resembles Pascal.
This is comp.lang.c. Your article is offtopic and inappriate here.

Keith Thompson (The_Other_Keith) ks***@mib.org <http://www.ghoti.net/~kst>
San Diego Supercomputer Center <* <http://users.sdsc.edu/~kst>
We must do something. This is something. Therefore, we must do this.  
P: n/a

Keith Thompson <ks***@mib.orgwrites:
"Ksitami" <ks*****@gmail.comwrites:
>function isprime(p:dword):boolean; var i,s:dword;
[snip]
You posted a program in some language that closely resembles Pascal.
This is comp.lang.c. Your article is offtopic and inappriate here.
Fumble fingers. I meant "inappropriate", of course.

Keith Thompson (The_Other_Keith) ks***@mib.org <http://www.ghoti.net/~kst>
San Diego Supercomputer Center <* <http://users.sdsc.edu/~kst>
We must do something. This is something. Therefore, we must do this.  
P: n/a

Ksitami wrote:
> http://mathworld.wolfram.com/TruncatablePrime.html
Incomprehensible. See below.

If you want to post a followup via groups.google.com, ensure
you quote enough for the article to make sense. Google is only
a poor interface to usenet. There is no reason to assume your
readers can, or ever will, see any previous articles.
More details at: <http://cfaj.freeshell.org/google/>
Also see <http://www.safalra.com/special/googlegroupsreply/>  
P: n/a

Ksitami wrote:
>
function isprime(p:dword):boolean;
This isn't C.
var i,s:dword;
dword is undefined. Invalid Pascal.
begin
result:=false;
result is undefined. Invalid Pascal.
if p<2 then exit;
This isn't even Pascal.
if p<4 then begin
result:=true;
exit
end;
if (p mod 2=0) or (p mod 3=0) then
exit;
i:=5; s:=round(sqrt(p));
while i<=s do begin
if p mod i=0 then exit;
i+=2;
if p mod i=0 then exit;
i+=4
end;
result:=true
end;
const
Nor is this. The const section precedes the var section.
nsp=5;
sp:array[1..nsp] of dword=(1,3,5,7,9);
And this is an abortion. Certainly not legal Pascal nor C
>
procedure x(r:dword);
var i:dword;
begin
if isprime(r) then begin
writeln(r:9);
for i:=1 to nsp do
x(r*10 + sp[i]);
end;
end;
begin
l:=0; lt:=0;
x(2); writeln(#10);
Illegal Pascal construct. Also illegal C.
x(3); writeln(#10);
x(5); writeln(#10);
x(7); writeln(#10);
writeln(lt);
end.
Epitome of uselessness.

Chuck F (cbfalconer at maineline dot net)
Available for consulting/temporary embedded and systems.
<http://cbfalconer.home.att.net>  
P: n/a

/* Righttruncatable primes:
A zerofree number n is called right truncatable if n and all numbers
obtained by successively removing the rightmost digits are prime.
There are exactly 83 right truncatable primes in base 10.
The first few are 2, 3, 5, 7, 23, 29, 31, 37, 53, 59, 71, 73, 79, 233,
239, 293, 311, 313, 317, 373, 379, 593, 599, ... (Sloane's A024770),
the largest being the 8digit number 73939133 (Angell and Godwin 1977).

Weisstein, Eric W. "Truncatable Prime." From MathWorldA Wolfram Web
Resource. http://mathworld.wolfram.com/TruncatablePrime.html */
#include <stdio.h>
typedef unsigned long int uint;
uint isprime(uint p) {
if (p<2) return 0;
if (p<4) return 1;
if (0==p%2  0==p%3) return 0;
uint i=5;
while (i*i <=p ){
if (p%i==0) return 0;
i+=2;
if (p%i==0) return 0;
i+=4; }
return 1;
}
uint sp[]={1,3,5,7,9,0};
uint k=0;
void x(uint r){
uint i;
if (isprime(r)){
printf("%3d %9d\n", ++k, r);
for (i=0; sp[i]!=0; i++)
x(r*10 + sp[i]); }
}
int main(){
x(2); x(3); x(5); x(7);
getchar();
return 0;
}  
P: n/a

uint isRTP(uint r) {
while (r>0) {
if (! isprime(r)) return 0;
r/=10; }
return 1; }  
P: n/a

"Ksitami" <ks*****@gmail.comwrites:
uint isRTP(uint r) {
while (r>0) {
if (! isprime(r)) return 0;
r/=10; }
return 1; }
Please provide context when you post a followup. Google Groups
formerly had a bug that made this difficult; that bug has been fixed,
but <http://cfaj.freeshell.org/google/still contains useful
information and links.
If you're going to post a chunk of code, you should say something
about it. I think I know what your isRTP function is trying to do,
but I don't know why you posted it.

Keith Thompson (The_Other_Keith) ks***@mib.org <http://www.ghoti.net/~kst>
San Diego Supercomputer Center <* <http://users.sdsc.edu/~kst>
We must do something. This is something. Therefore, we must do this.  
P: n/a

actually i origionally posted it in trying to fing a right prime which
is a number that all the numbers in the numbers is prime. say 573. the
3 5 and 7 are all prime. somehow the number needs to be broken down
divisibly by 10 for each character and then checked for prime.
simon
Keith Thompson wrote:
"Ksitami" <ks*****@gmail.comwrites:
uint isRTP(uint r) {
while (r>0) {
if (! isprime(r)) return 0;
r/=10; }
return 1; }
Please provide context when you post a followup. Google Groups
formerly had a bug that made this difficult; that bug has been fixed,
but <http://cfaj.freeshell.org/google/still contains useful
information and links.
If you're going to post a chunk of code, you should say something
about it. I think I know what your isRTP function is trying to do,
but I don't know why you posted it.

Keith Thompson (The_Other_Keith) ks***@mib.org <http://www.ghoti.net/~kst>
San Diego Supercomputer Center <* <http://users.sdsc.edu/~kst>
We must do something. This is something. Therefore, we must do this.
  This discussion thread is closed Replies have been disabled for this discussion.   Question stats  viewed: 3163
 replies: 25
 date asked: Nov 8 '06
