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C Compiler error?

P: 2
a[4] = 0; a[3 = 0; a[2] = 0; a[1] = 0; a[0] = 0;

are the results from the printf() in the following program using an old Borland C++ (V4.5) compiler.

#include <stdio.h>
int a[] = {0, 1, 2, 3, 4};
int main( ) {
int *p;
for (p = a+4; p >= a; p--)
printf ("a[%d] = %d;\t", (p-a), a[p-a]);
return 0;
}

When I assigned an integer i = p-a; in the 'for loop' then replaced (p-a) and a[p-a] with i, and a[i], respectively - the program prints OKAY!

When I stepped through the above code using Borland C debugger, I got this message : "Conversion might loose significant digits." when I evaluate a[p-a]!

Then again, if I replace the above printf() with

printf ("%d;\t", a[p-a]);

then I got what were expected: 4; 3; 2; 1; 0
BUT the debugger still generated the above "Conversion..." message when I evaluated a[p-a]!

So, Is this a case of compiler error / or is there a subtle concept in C language that I miss?


Thanks,
EE02IU
Nov 5 '06 #1
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