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# How to count some repetitions

 P: n/a Hi, I am a new user of C++ and I am learning this language. I want to resolve this example: 1) I have an indefinite sequence of integer (from 0 to 36) as Input; 2) I want to know the maximum number of occurrences and its value. eg Input: 0, 2, 5, 2, 23, 11, 11, 23, 15, 17, 25, 11, 23, 18, 23 (Ctrl+z) Output: Value is 23 Occurences is 4 For the input I have written this code: iNumber = 0; // Counter while (1) { //read next cout << "Enter number (Ctrl-z = Input End): "; cin >myNumber; if (cin.eof()) break; //update the counter iNumber++; } But I am in difficulty, when I try to resolve the second step. The solution don't have to use the array. I hope in Your help in order to resolve my problem without array or map or struct. Thank You and Best Regards Nino Nov 1 '06 #1
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 P: n/a "nick048" myNumber; Okay, you input myNumber, but you aren't doing anything with it. You probably want to store it somewhere, prehaps a std::vector. Code fragments, since this looks suspiciously like homework, but you did show some code, so I can show you some. #include .... std::vector::iterator it = Data.begin(); it != Data.end(); ++it ) { // Do something with *it here which will be one of the numbers. } > But I am in difficulty, when I try to resolve the second step. The solution don't have to use the array. I hope in Your help in order to resolve my problem without array or map or struct. Thank You and Best Regards Nino Look at what I read, read up on vectors, try to use them to solve your problem. If you get stuck again, show your code and where you get stuck. Nov 1 '06 #2

 P: n/a In article <11**********************@e64g2000cwd.googlegroups .com>, "nick048" myNumber; if (cin.eof()) break; //update the counter iNumber++; } But I am in difficulty, when I try to resolve the second step. The solution don't have to use the array. I hope in Your help in order to resolve my problem without array or map or struct. You are braking the problem down the wrong way (or not breaking it down enough as the case may be.) You should take a "verticle slice" of the problem. This means instead of trying to do the "first step" to completion, you should try to do all the steps, but with a limited data set. So for example, get your program working for just one input value. I.E., make a program that can accept a single number as input and print the correct result. Then modify your program to accept two values, then three, &c. By the time you get to three, you should start seeing where you can use loops and arrays to remove duplication, and thus have a general solution that can work with any number of inputs. Here is a little something to get you started: int main() { cout << "Enter a number from 0 to 36: "; int number = -1; cin >number; assert( number >= 0 && number <= 36 ); // need real error checking? cout << "The most numerous in the sequence is: " << number; cout << "It occurs " << 1 << "time(s)."; } Now modify the above so it will work with more than one input where all the values entered are the same. When you get that working post your result back here and we'll help you with the next step. -- To send me email, put "sheltie" in the subject. Nov 1 '06 #3

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