How do i convert a float to string?

[cool17]

hi guys

I am writing a code for to covert expression to string so how is this going to be possible in C?

i know for string to float is using atof() so what about the other way round?

thx

[vermarajeev]

hi guys

I am writing a code for to covert expression to string so how is this going to be possible in C?

i know for string to float is using atof() so what about the other way round?

thx

Here is your solution

int main()
{
    char* str = new char[30];
 
    float flt = 2.4567F;
    sprintf(str, "%.4g", flt );    
    cout<<str<<endl;
    return 0;
}

Thankx

[tyreld]

You can use "snprintf" to accomplish this.

int snprintf(char *str, size_t size, const char *format, ...);

Upon successful return, this function returns the number of characters printed (not including the trailing '\0' used to end output to strings). The function snprintf() does not write more than size characters (including the trailing '\0'). If the output was truncated due to this limit then the return value is the number of characters (not including the trailing '\0') which would have been written to the final string if enough space had been available. Thus, a return value of size or more means that the output was truncated. (See also below under NOTES.) If an output error is encountered, a negative value is returned.

You will notice in this example that if you run it the string is reported as truncated. This is because by default the %f format has a percision of 6 decimal places. Change %f to %.2f and rerun it.

#include <stdio.h>
 
#define SIZE 10
 
int main(void)
{
   char buf[SIZE];
   int result = 0;
   float value = 154.78;
 
   result = snprintf(buf, SIZE, "%f", value);
   if (result >= SIZE)
       printf("The string has been truncated\n");
 
   printf("The string value of the floating value = %s\n", buf);
 
   return 0;
}
 

[tyreld]

Here is your solution

int main()
{
    char* str = new char[30];
 
    float flt = 2.4567F;
    sprintf(str, "%.4g", flt );    
    cout<<str<<endl;
    return 0;
}

Thankx

Using "sprintf" is a poor choice as it can overrun the provided string buffer if you are careless. Using functions that allow you to control the the size of input copied into a buffer is always the best coding practice. In this case "snprintf" is a better choice.

[vermarajeev]

I get this error when I use snprintf

error C3861: 'snprintf': identifier not found, even with argument-dependent lookup

I'm using Microsoft Visual Studio .NET on my system

Thankx....

[tyreld]

I think that it is defined as "_snprintf" on windows.

[vermarajeev]

I think that it is defined as "_snprintf" on windows.

thankx it works fine.....

[srvardhan]

Here is your solution

int main()
{
    char* str = new char[30];
 
    float flt = 2.4567F;
    sprintf(str, "%.4g", flt );    
    cout<<str<<endl;
    return 0;
}

Thankx

There is one easy method using this u can convert from any data type to any other data type

Just include the sstream header file

let
string strSalary = "5449.98";
float SalaryInFloat;

istringstream mySalaray(strSalary);
mySalaray >> SalaryInFloat

thats it

Rajavardhan Sarkapally

[JosAH]

There is one easy method using this u can convert from string data type to any other data type

Just include the sstream header file

let
string strSalary = "5449.98";
float SalaryInFloat;

istringstream mySalaray(strSalary);
mySalaray >> SalaryInFloat

thats it

Rajavardhan Sarkapally

Ern, the OP asked for something the other way around if I'm not mistaken.

kind regards,

Jos

[NinjaSkitch]

Same basic idea, except using an ostream:

ostringstream s;
s << 2.5;
cout << s.str();