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Arrays and pointers

I have a problem that says modify a problem I have already done. but I have to use pointer notation instead of array notation. Could someone explain the difference to me.
Oct 6 '06 #1
2 1287
m013690
23
to access a member in an array, you would use:

array[ 4 ]

to access the same item with pointer notation you could say:

*( array + 4 )
Oct 6 '06 #2
tyreld
144 100+
Here is an illustrative example.

Expand|Select|Wrap|Line Numbers
  1.  
  2. int array[4] = { 0, 1, 2, 3 };
  3. int *array_ptr1, *array_ptr2;
  4.  
  5. // we assign array_ptr1 to the address for the first element.
  6. array_ptr1 = &array[0];  
  7.  
  8. // C provides a shorthand for dealing with arrays. We can write the following
  9. // to accomplish the same task.
  10. array_ptr2 = array;
  11.  
  12. if (array_ptr1 == array_ptr2)
  13.   printf("This will always be true because both pointers contain the same value.\n");
  14.  
  15. // Array indices are just doing pointer arithmetic in the background.
  16. printf("Value at index 2 via array index = %d\n", array[2]);
  17. printf("Value at index 2 via pointer addition = %d\n", *(array_ptr1 + 2));
  18.  
  19.  
Oct 6 '06 #3

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