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unkown number of nested for loops

P: n/a
Hi, Somehow I can't figure this one out.

I have an integer variable N and this N reflects the amount of nested
for loops. I mean

if N = 1, the I have

for (int i1 = ....) {
<code>
}

if N = 2, I have

for (int i1 = ...)
for (int i2 = ...) {
<code>
}

....

if N = n I must have

for (int i1 = ...)
....
for (int in = ...) {
<code>
}
Is there a way to program this disregarding the value of N?

thanks
Sep 21 '06 #1
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P: n/a
In article <ee**********@gaudi2.UGent.be>,
Klaas Vantournhout <no************@spam.comwrote:
>Hi, Somehow I can't figure this one out.
>I have an integer variable N and this N reflects the amount of nested
for loops. I mean
>if N = n I must have
>for (int i1 = ...)
...
for (int in = ...) {
<code>
}
>Is there a way to program this disregarding the value of N?
int *indices = malloc(N * sizeof(int));

then indices[N-1] corresponds to iN
--
I was very young in those days, but I was also rather dim.
-- Christopher Priest
Sep 21 '06 #2

P: n/a
Klaas Vantournhout wrote:
Hi, Somehow I can't figure this one out.

I have an integer variable N and this N reflects the amount of nested
for loops. I mean

if N = 1, the I have

for (int i1 = ....) {
<code>
}

if N = 2, I have

for (int i1 = ...)
for (int i2 = ...) {
<code>
}

...

if N = n I must have

for (int i1 = ...)
...
for (int in = ...) {
<code>
}
Is there a way to program this disregarding the value of N?

thanks
It depends on the value of the upper bound and lower bound obviously
In case all are the same, (upper-lower)^n will do.

For instance:
for (i=0; i<10;i++)
for (j=0; j<10;j++)

<code>

is the same as

for (i=0; i<100; i++)

<code>

100=(10 - 0) ^ 2

jacob
Sep 21 '06 #3

P: n/a
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Hash: SHA1
Klaas Vantournhout wrote:
Hi, Somehow I can't figure this one out.

I have an integer variable N and this N reflects the amount of nested
for loops. I mean

if N = 1, the I have

for (int i1 = ....) {
<code>
}

if N = 2, I have

for (int i1 = ...)
for (int i2 = ...) {
<code>
}

...

if N = n I must have

for (int i1 = ...)
...
for (int in = ...) {
<code>
}
Is there a way to program this disregarding the value of N?
You /could/ do it with recursion.

i.e.

void function(level)
{
int counter;

for (counter = 1; counter < 10; ++counter)
{
if (level == 0)
{
/* do usefull work */
}
else function(level-1);
}
}

- --
Lew Pitcher

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Sep 21 '06 #4

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