424,984 Members | 1,009 Online Need help? Post your question and get tips & solutions from a community of 424,984 IT Pros & Developers. It's quick & easy.

I don't even know where to start

 P: 5 Intro level problem; should be easy Given an int variable k that has already been declared, use a while loop to print a single line consisting of 97 asterisks. Use no variables other than k . Sep 18 '06 #1
7 Replies

 P: 61 Here your aim is to print 97 asterisks in one line. So you have to start a counter and let k be the counter and initialise it by 0. Now start a while loop with the condition that is k < 97(see your counter starts with 0). Inside the loop print one asterisk and increment the counter. So the loop will keep on printing the asterisks for k=0,1,2,.......,96 and when the value of k will become 97 the loop terminates and you will get 97 asterisks in one line. So give a try. Sep 19 '06 #2

 P: 12 hi pukur123,i have try and it is like this........it's right....and i get the "*" print 97 times in a straight lines.... like this.. * * * * * * * . . . . .. thanks ya #include using namespace std; int main() { int k=0; while(k<97) { cout<<"*"<

 P: 61 Try this one.... #include using namespace std; int main() { int k=0; while(k<97) { cout<<"*\n"<

 100+ P: 293 If you want a row of 97 asterisks, instead of a column of 97 asterisks, The output statement should be cout << "*"; instead of cout << "*" << endl; Sep 19 '06 #5

 P: 12 thanks,i am much clearer now..better understanding...(*_*) Sep 20 '06 #6

 P: 3 Intro level problem; should be easy Given an int variable k that has already been declared, use a while loop to print a single line consisting of 97 asterisks. Use no variables other than k . hi, i am writing a sample code for that in my standard as follows int k; k = 1; while( k <= 97) { printf("*"); k++; } Sep 20 '06 #7

 P: 27 int k=97; while(k--) cout << '*'; Sep 20 '06 #8 