date formating

[AlekseyUS]

Hi all,

the following is a chunk of my code:

char timebuf[10];
char datebuf[10];
_strtime( timebuf );
_strdate( datebuf );

cout<<timebuf<<endl; //output: 15:48:59
cout<<datebuf<<endl; //output: 09/14/06

what is the simplest way to format the date to look like 09-14-2006

PS:I have all the necessary libraries included.

Thanks a lot

[pukur123]

There is no function to change the date to the format you required. Just access the position of colon in the buffer datebuf and change the colon to hyphen.

[AlekseyUS]

Ok i just did simple array formatting however it was giving me casting problems when i was jsut trying to do...

datebuf[2] = "-"; // why was this causing the following issue?

error C2440: '=' : cannot convert from 'char [2]' to 'char'
This conversion requires a reinterpret_cast, a C-style cast or function-style cast

Finally i decided to go through ASCII unable to resolve the above problem:

char timebuf[10];
char datebuf[10];
const unsigned char asciiDash(45);
_strtime( timebuf );
_strdate( datebuf );
datebuf[2] = asciiDash;
datebuf[5] = asciiDash;

and got 09-15-06...

[pukur123]

See the assignment you are done......

datebuf[2] = "-"; // why was this causing the following issue?


Lefthand side is a character and the right hand side is a string which is of type (char *). So the RHS is not compatible with the LHS. Hence the issue.

See the difference between single quotes and double quotes.

Make the assignment like this.....

datebuf[2] = '-';