memory allocation for arrays in c++

[nagarajanj]

#include<conio.h>
#include<iostream.h>
#include<stdio.h>

void main()
{
int x[5] = {1,2,3,4,5};
int i = 0;
int y[5]={5,4,3,2,1};
int result[5]={21,0,0,0,0};



clrscr();
for(i = 0; i <=5; i++)
{
cout << x[i] << "\t" << y[i] << "\t" << result[i] << endl;
}
cout << "\n";

for(i=0;i<=5; i++)
{
printf("%u(%d) ",&x[i], x[i]);
}
cout << endl;
for(i=0;i<=5; i++)
{
printf("%u(%d) ",&y[i], y[i]);
}
cout << endl;
for(i=0;i<=5; i++)
{
printf("%u(%d) ",&result[i],result[i]);
}
cout <<endl;
i = 0;
while(i++ < 5)
{
result[i] = x[i] - y[i];
}
for(i = 0; i <=5; i++)
{
cout << x[i] << "\t" << y[i] << "\t" << result[i] << endl;
}

getch();
}

The output is
x y result
1 -1 21
2 4 -2
3 3 0
4 2 2
5 1 4

please explain how these answer is possible ? mainly how array elements are allocated in memory?

[Banfa]

No the output is

1       5       21
2       4       0
3       3       0
4       2       0
5       1       0
-858993460      -858993460      -858993460
 
1245008(1)  1245012(2)  1245016(3)  1245020(4)  1245024(5)  1245028(-858993460)
1244968(5)  1244972(4)  1244976(3)  1244980(2)  1244984(1)  1244988(-858993460)
1244940(21)  1244944(0)  1244948(0)  1244952(0)  1244956(0)  1244960(-858993460)
1       5       21
2       4       -2
3       3       0
4       2       2
5       1       4
-858993460      -858993460      0

You never calculate the result for index 0 because of the increment in the while loop and most of your for loops ( for (i=0; i<=5; i++) ) go round 6 times instead of 5 accessing memory that is not allocated.