What happens when I write struct xx_type {...}

[Joakim Hove]

Hello,

to promote data-hiding I have come across the following technique,
which I quite like:

Header file xxx.h:
------------------
typedef struct xxx_type xxx_type;
xxx_type * xxx_alloc(int);
-------------------------

Source file xxx.c:
-----------------
struct xxx_type {
double *data;
int size;
};

xxx_type * xxx_alloc(int size) {
xxx_type *xxx;
xxx = malloc(sizeof *xxx);
xxx->size = size;
....
return xxx;
}
-------------------------
What I wonder is what really happens at the struct xxx_type {};
statement in the source file. To me it seems like a struct is defined,
but it is not used for anything - i.e. not for a typedef nor to
instantiate an object.

So - I guess I my question is really: "What does the compiler do -
when it meets a

struct foo {
....
....
};

statement.
Best Regards

Joakim Hove

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[CBFalconer]

Joakim Hove wrote:

>

.... snip ...

>
So - I guess I my question is really: "What does the compiler do -
when it meets a

struct foo {
....
....
};

statement.

It defines a new type, known as "struct foo", which you can now use
in defining storage, parameters, etc. typedef DOES NOT define a
new type, it simply defines a synonym for the already defined type.

--
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