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decaying of array

Hi.I know that when an array name is used with the sizeof() operator,it
does not decay into a pointer.Is there any other situation when the
decaying to a pointer thing does not happen.Thanks for help.Eric

Aug 10 '06 #1
4 1220


di**********@yahoo.com wrote On 08/10/06 14:18,:
Hi.I know that when an array name is used with the sizeof() operator,it
does not decay into a pointer.Is there any other situation when the
decaying to a pointer thing does not happen.Thanks for help.Eric
FAQ, Question 6.3.

http://www.c-faq.com/

--
Er*********@sun.com

Aug 10 '06 #2
di**********@yahoo.com wrote:
Hi.I know that when an array name is used with the sizeof()
operator
It's the sizeof operator, not the sizeof() operator. We just went over
this in another thread.


Brian
Aug 10 '06 #3
di**********@yahoo.com wrote:
Hi.I know that when an array name is used with the sizeof() operator,it
does not decay into a pointer.Is there any other situation when the
decaying to a pointer thing does not happen.Thanks for help.Eric
When it is the operand of &
Aug 11 '06 #4
"Nils O. Selåsdal" <NO*@Utel.nowrites:
di**********@yahoo.com wrote:
>Hi.I know that when an array name is used with the sizeof() operator,it
does not decay into a pointer.Is there any other situation when the
decaying to a pointer thing does not happen.Thanks for help.Eric

When it is the operand of &
Or when it's a string literal used to initialize an array.

--
Keith Thompson (The_Other_Keith) ks***@mib.org <http://www.ghoti.net/~kst>
San Diego Supercomputer Center <* <http://users.sdsc.edu/~kst>
We must do something. This is something. Therefore, we must do this.
Aug 11 '06 #5

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