strtod(*iter) + double

[Gary Wessle]

Hi

I have a
vector<stringwhich holds numbers, I need to loop and printout those
numbers + a value as doubles .

typedef vector<string>::const_iterator vs_itr;
for(vs_itr i=vect.begin(); i!=vect.end(); ++i){
cout << *i << '\t' << strtod(*i)+val << '\n';

isn't de-referencing the iterator puts out its string value?

I am getting

gen_data.cpp:62: error: cannot convert 'const std::basic_string<char,
std::char_traits<char>, std::allocator<char' to 'const char*' for
argument '1' to 'double strtod(const char*, char**)'

thanks

[Ian Collins]

Gary Wessle wrote:

Hi

I have a
vector<stringwhich holds numbers, I need to loop and printout those
numbers + a value as doubles .

typedef vector<string>::const_iterator vs_itr;
for(vs_itr i=vect.begin(); i!=vect.end(); ++i){
cout << *i << '\t' << strtod(*i)+val << '\n';

isn't de-referencing the iterator puts out its string value?

I am getting

gen_data.cpp:62: error: cannot convert 'const std::basic_string<char,
std::char_traits<char>, std::allocator<char' to 'const char*' for
argument '1' to 'double strtod(const char*, char**)'

The error is telling exactly what's wrong, strtod takes a const char*,
not a std::string. Look up string.c_str()

--
Ian Collins.

[Gary Wessle]

Ian Collins <ia******@hotmail.comwrites:

Gary Wessle wrote:

>Hi

I have a
vector<stringwhich holds numbers, I need to loop and printout those
numbers + a value as doubles .

typedef vector<string>::const_iterator vs_itr;
for(vs_itr i=vect.begin(); i!=vect.end(); ++i){
cout << *i << '\t' << strtod(*i)+val << '\n';

isn't de-referencing the iterator puts out its string value?

I am getting

gen_data.cpp:62: error: cannot convert 'const std::basic_string<char,
std::char_traits<char>, std::allocator<char' to 'const char*' for
argument '1' to 'double strtod(const char*, char**)'

The error is telling exactly what's wrong, strtod takes a const char*,
not a std::string. Look up string.c_str()

--
Ian Collins.

I actually was trying to fix it using

out<< setw(10) << *i << strtod(*i.c_str(),0)+val << '\n';
for no avail, here the *i puts out a string, c_str() converts it to a
char*, why is it complaining still?
saying vs_itr' has no member named 'c_str', then what am going to
apply c_str() upon? should I cast *i into a string?

[Thomas J. Gritzan]

Gary Wessle schrieb:

out<< setw(10) << *i << strtod(*i.c_str(),0)+val << '\n';
for no avail, here the *i puts out a string, c_str() converts it to a
char*, why is it complaining still?
saying vs_itr' has no member named 'c_str', then what am going to
apply c_str() upon? should I cast *i into a string?

Look up the operator precedence table:

"." has higher precedence than prefix-*, so *i.c_str() is parsed as
*(i.c_str()), but you want (*i).c_str() or simply i->c_str()

Instead of strtod, you could use the method that is in the FAQ:
http://www.parashift.com/c++-faq-lit....html#faq-39.2

--
Thomas

[red floyd]

Gary Wessle wrote:

Ian Collins <ia******@hotmail.comwrites:

>Gary Wessle wrote:

>>Hi

I have a
vector<stringwhich holds numbers, I need to loop and printout those
numbers + a value as doubles .

typedef vector<string>::const_iterator vs_itr;
for(vs_itr i=vect.begin(); i!=vect.end(); ++i){
cout << *i << '\t' << strtod(*i)+val << '\n';

isn't de-referencing the iterator puts out its string value?

I am getting

gen_data.cpp:62: error: cannot convert 'const std::basic_string<char,
std::char_traits<char>, std::allocator<char' to 'const char*' for
argument '1' to 'double strtod(const char*, char**)'

The error is telling exactly what's wrong, strtod takes a const char*,
not a std::string. Look up string.c_str()

--
Ian Collins.

I actually was trying to fix it using

out<< setw(10) << *i << strtod(*i.c_str(),0)+val << '\n';
for no avail, here the *i puts out a string, c_str() converts it to a
char*, why is it complaining still?
saying vs_itr' has no member named 'c_str', then what am going to
apply c_str() upon? should I cast *i into a string?

Try strtod( (*i).c_str(), 0).

the . operator binds tighter that '*', so you had the equivalent of
*(i.c_str()), which won't work.